You are correct...amplitude will be the answer
Could u put it in english u can use goggle translation if u do not know how to
For figure one the “+” are protons and the “-“ are electrons for the second one the middle is the nucleus and the other is the orbit
Answer:
Change in Q = 2.1x 10^-3 C
Explanation:
We are given that
The Initialcapacitance C1 = 6.0μF
Initial charge oncapacitor
Q1 = C1 V
= 6.00 x 10^-6 x 100
= 6.00 x 10^-4 C
So the Final capacitance C2 will be
= K x C1 = 4.5 x 6.00 x 10^-6
= 2.7 x 10^ -5 F
So to get Finalcharge
We use Q2 = C2 x V
= 2.7 x 10^ - 5 x 100
= 27 x 10^ -4 C
So Charge flown in thecapacitor is change in Q
Which is = Q2 - Q1
= 27 x 10^-4 - 6.0 x 10^ -4
Change in Q = 2.1x 10^-3 C
Microscope use to observe microscopic organisms such as bacteria, viruses, and others. The spontaneous observation that microorganisms move and transport through the air which serves as their medium or channel to transfer from one place to another. This microbiology or study with the use of the microscope greatly affects and contributed to the foul air theory on which traces of the sources of disease became the focus of their study. Diseases and properties of microorganisms, as well as, the solution on how to cure and fight these becomes possible with the availability of microscope.
