Answer:1.8 hr
Explanation:
Given
mass of cargo=500,000 kg
initial speed
Frictional force=85 v
at t=0 engine is shut off so acquired speed is slowly decreasing


Integrating both sides


t=6462.425 s
t=1.8 hr
Answer:
Isothermal : P2 = ( P1V1 / V2 ) , work-done 
Adiabatic : : P2 =
, work-done =
W = 
Explanation:
initial temperature : T
Pressure : P
initial volume : V1
Final volume : V2
A) If expansion was isothermal calculate final pressure and work-done
we use the gas laws
= PIVI = P2V2
Hence : P2 = ( P1V1 / V2 )
work-done :

B) If the expansion was Adiabatic show the Final pressure and work-done
final pressure

where y = 5/3
hence : P2 = 
Work-done
W = 
Where 
newtons first law states that a object in motion will stay in motion unless acted on by an outside force and an object at rest will stay at rest for the same reason. the force of a moving object is equal to its mass times its acceleration.
Given that the velocity of a car increases by 40 m/s in 80 seconds, the acceleration of the car will be given by:
a=(final velocity-initial velocity)/(time)
thus;
final velocity=40 m/s
initial velocity=0
time=80 seconds
hence;
a=(40-0)/80
=0.5m/s^2