1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
notka56 [123]
2 years ago
10

–3(c + 14) + 3 = 15 solve for c

Mathematics
2 answers:
lawyer [7]2 years ago
8 0

Answer:

c = -18

Step-by-step explanation:

We need to distribute the -3 to each term within the parentheses. This essentially means finding the sum of the product of -3 with each of those inner terms:

-3 * c + (-3) * 14 + 3 = 15

-3c - 42 + 3 = 15

-3c = 15 + 42 - 3 = 54

c = 54/(-3) = -18

c = -18

Natasha2012 [34]2 years ago
5 0

Answer:

<h2>c = -18</h2>

Step-by-step explanation:

–3(c + 14) + 3 = 15

⇔

–3c - 42 + 3 = 15

⇔

-3c = 15 + 42 - 3

⇔

-3c = 54

⇔

c = - 54/3

⇔

c = -18

You might be interested in
a scale model of a school building is 5 inches tall. If the building is 100 feet tall, find the scale of the model
Maslowich
It's 20 feet to one inch or 10 feet to half an inch.
7 0
2 years ago
Read 2 more answers
Mole Conversion:<br> What is the mass of 3.13 x 1023 molecules of carbon dioxide?
4vir4ik [10]

Answer:

The mass of 3.13*10²³ molecules of carbon dioxide is 22.88 g.

Step-by-step explanation:

Avogadro's Number or Avogadro's Constant is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ molecules are present in 1 mole, 3.13*10²³ molecules are present in how many moles?

moles=\frac{3.13*10^{23}molecules*1 mole }{6.023*10^{23}molecules}

moles= 0.52

Since the molar mass of carbon dioxide is 44 g / mole, then the following rule of three can be applied: if there are 44 g in 1 mole, how much mass is there in 0.52 moles?

mass=\frac{0.52 moles*44 g}{1 mole}

mass= 22.88 g

<u><em>The mass of 3.13*10²³ molecules of carbon dioxide is 22.88 g.</em></u>

8 0
2 years ago
Use the compass and ruler to construct the bisector of the angle given below.
soldier1979 [14.2K]
Okay so I think you go south now give me ma points
8 0
2 years ago
26) Write the equation of the circle with center (0, 0) and (3, 6) a point on the circle. A) x2 + y2 = 9 B) x2 + y2 = 30 C) x2 +
alexdok [17]

Answer:C) x2 + y2 =45

Step-by-step explanation:

The equation of a circle in standard form is (x-h)2+(y-k)2=r2.

Since you know the center is (0,0), you can sub this is value in for h and k, then use the point (3,6) to sub in for x and y and you will find r2 =45. Hope that helps :)

4 0
2 years ago
Read 2 more answers
PLEASE HELP!!
pogonyaev

Answer:

Work shown below!

Step-by-step explanation:

\sqrt{-18}=\sqrt{18i^{2} }  =\sqrt{2*9i^{2} }=3i\sqrt{2}

2\sqrt{-16} =2\sqrt{16i^{2} } =4i*2=8i

4 0
2 years ago
Other questions:
  • Donna Bakes biscuits on a rectangular cookie sheet that is 30 centimeters by 50 centimeters.Each biscuit had a diameterof 8 cent
    13·1 answer
  • On a piece of paper graph f(x)=-1
    15·2 answers
  • Ted can clear a football field of debris in 3 hours. Jacob can clear the same field in 2 hours. When they work together, the
    5·2 answers
  • Suppose in one year, total revenues from digital sales of pop/rock, tropical (salsa/merengue/cumbia/bachata), and urban (reggaet
    5·1 answer
  • Clover picks a positive number.What is true about the opposite of her number?
    11·2 answers
  • Which best describes the function represented by the table?
    10·1 answer
  • What is not an input for a function?
    6·2 answers
  • There are 50 animals in a shelter. Sixty percent of the animals are dogs. Which equation can be used to find the number of dogs
    8·2 answers
  • An equation for a line with a slope of zero.
    9·2 answers
  • What is the sum of the polynomials?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!