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Len [333]
3 years ago
12

Which function transforms the graph of y= x^2 so that it is first shifted down 4 units and its then reflected across the y- axis

?
A. y= -x^2 +4
B. y= -x^2 - 4
C. y= ( -x)^2 -4
D. y= - ( x + 4 )^2
Mathematics
1 answer:
GaryK [48]3 years ago
8 0

Answer:

Option C. y= ( -x)^2 -4

Step-by-step explanation:

If we have a function f(x) = ax ^ 2 and we want to transform it into a function g(x) that is equal to f(x) displaced c units down on the y-axis, then we must do:

g(x) = f(x) -c

In this case we want to move the function 4 units down, then:

g(x) = f(x) -4\\\\g(x) = x ^ 2 -4

Finally, to reflect the function on the y-axis. must do y = g(-x)

Then we have the following function:

g(-x) = (-x) ^ 2 -4\\\\y = (-x) ^ 2 -4

The answer is option C

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5x = -25 what is the answer of x
Sliva [168]

Answer:

x= -5

Step-by-step explanation:

just use a calculator

5 0
3 years ago
For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of
Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

S=\frac{a}{1-r} [Here r is less than 1]

S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

S = \frac{1}{3}

Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

3 0
3 years ago
PLEASE HELP ASAP!!!!!!!! I ONLY HAVE 20 MORE MINUTES AND I HAVE LIKE EIGHT MORE QUESTIONS!!!
sertanlavr [38]

Answer:

I'm pretty sure its -4-12x but I could be wrong

Step-by-step explanation:

First I tried to solve for x but got -12x+4 so to get 4 on the other side of the equation I subtracted and got -4-12x I hope this helps :)

7 0
2 years ago
Please helpppppppp -2p-4=2
OlgaM077 [116]

p = -3

Step-by-step explanation:

-2p-4=2

add 4 both sides

-2p-4+4=2+4

-2p=6

divide -2 both sides

-2p/-2=6/-2

p = -3

hope it's helpful ❤❤❤

THANK YOU.

5 0
3 years ago
How do you do this function (-3p - 4)(2p + 5)
kakasveta [241]

Answer: The answer is −6p^2-23p-20

6 0
3 years ago
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