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4 years ago

Add the complex numbers. (5-2i)+(2+4i)

Mathematics

1 answer:

Ksju [112]4 years ago

3 0

Answer:

2i + 7

Step-by-step explanation:

Given

(5 - 2i) + (2 + 4i) ← remove parenthesis

= 5 - 2i + 2 + 4i ← collect like terms

= 2i + 7

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Factor the following expression. x² - 10x +9 2 Factor the following expression . x² - 10x +9 2

deff fn [24]

Answer:

x² - 10x + 9 = (x-9)(x-1)

the factored expression would be (x-9)(x-1)

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2 years ago

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Determine if each pair of ratios forms a proportion. 3 to 5, 12 to 16

Sati [7]

Answer:

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3 years ago

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pickupchik [31]

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3 years ago

Solve x^2 + 6x - 5 = 0 by completing the square.

Nezavi [6.7K]

Answer:

(x + 3)² = 14

Step-by-step explanation:

x² + 6x - 5 = 0

Add 5 and 9 on both sides.

x² + 6x + 9 = 14

Factor left side.

(x + 3)² = 14

Take the square root on both sides.

(x + 3) = ±√14

Subtract 3 on both sides.

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6 0

4 years ago

A bookstore can purchase several calculators for a total cost of $120. If each calculators cost $1 less, the bookstore could pur

Tresset [83]

$x-number\ of\ calculators\ sold\ in\ regular\ price\\\\
y-\ \ first\ price\\\\
(y-1)\ \ -second\ price\\\\x=\frac{120}{y}\\
x+10=\frac{120}{y-1}\\\\Substitude\ x=\frac{120}{y}\ into\ the\ second\\\\\
\frac{120}{y}+10=\frac{120}{y-1}\ \ |-\frac{120}{y-1}-10\\\\
\frac{120}{y}-\frac{120}{y-1}=-10\\\\Make\ a\ common\ denominator\\\\
\frac{120(y-1)}{y(y-1)}-\frac{120y}{(y-1)y}=-10
\frac{120y-120)}{y(y-1)}-\frac{120y}{(y-1)y}=-10\\\\
\frac{120y-120-120y}{y(y-1)}=-10$ <u /> $Assumptions:\\y \neq 0\ \ \ and\ \ y \neq 1\\\\ \frac{-120}{y(y-1)}=-10\ \ \ | *y(y-1) \\\\
-120=-10y(y-1)\\\\
-120=-10y^2+10y\\\\
10y^2-10y-120=0\ \ \ |:10\\\\
y^2-y-12=0\\\\Factor\ equation\\\\ y^2+3y-4y-12=0\\\\
(y-4)(y+3)=0\\\\Solutions:\ \ y=4\ \ and\ \ y=-3$

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4 years ago