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3 years ago

A physical system that is isolated from its environment is:

Physics

1 answer:

kompoz [17]3 years ago

8 0

Closed

Explanation:

A physical system that is isolated from its environment is said to be a closed system.

In a closed system, energy can be exchange but matter cannot be exchanged.

A closed system sightly permits the only certain types of exchange.
These systems are usually used to control and limit the impact of the environment on a system.
Experiments can be conducted on the premises of any the interactions.

Learn more:

Momentum of an isolated system brainly.com/question/7973509

#learnwithBrainly

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if a stone with an original volcity of 0 is falling from the ledge and takes 8 seconds to hit the ground what is the final volci

Nookie1986 [14]

On Earth, gravity adds 9.8 m/s to the downwsrd speed of any falling object, every second. Beginning from zero downward speed, the speed grows to (8 x 9.8) = 78.4 m/s downward after 8 sec.

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3 years ago

A perfectly flexible cable has length L, and initially it is at rest with a length Xo of it hanging over the table edge. Neglect

zaharov [31]

Answer:

$X=X_o+\dfrac{1}{2}gt^2$

Explanation:

Given that

Length = L

At initial over hanging length = Xo

Lets take the length =X after time t

The velocity of length will become V

Now by energy conservation

$\dfrac{1}{2}mV^2=mg(X-X_o)$

$V=\sqrt{2g(X-X_o)}$

We know that

$\dfrac{dX}{dt}=V$

$\dfrac{dX}{dt}=\sqrt{2g(X-X_o)}$

$\sqrt{2g}\ dt=(X-X_o)^{-\frac{1}{2}}dX$

At t= 0 ,X=Xo

So we can say that

$X=X_o+\dfrac{1}{2}gt^2$

So the length of cable after time t

$X=X_o+\dfrac{1}{2}gt^2$

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3 years ago

When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to

Serjik [45]

Answer:

E) d/sqrt2

Explanation:

The initial electric force between the two charge is given by:

$F=k\frac{q_1 q_2}{d^2}$

where

k is the Coulomb's constant

q1, q2 are the two charges

d is the separation between the two charges

We can also rewrite it as

$d=\sqrt{k\frac{q_1 q_2}{F}}$

So if we want to make the force F twice as strong,

F' = 2F

the new distance between the charges would be

$d'=\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{1}{\sqrt{2}}\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{d}{\sqrt{2}}$

so the correct option is E.

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3 years ago

What is the frequency of the most intense radiation emitted by your body? assume a skin temperature of 95 ∘f?

navik [9.2K]

Answer:
Wien's law:
Î»_peak = b/T
Wien's constant: b = 2.8977685(51)Ă—10â’3 mâ€˘K
T = (5/9)[96 â€“ 32) + 273 = 35.55 + 273 = 308.55 deg. K
Î»_peak = 2.8977685(51)Ă—10â’3 /308.55 = 9.39x10^-6 = 9.39 um

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3 years ago

What two factors will most likely change the speed of a mechanical wave?

iVinArrow [24]

Period and wavelength

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3 years ago