All categories

3 years ago

A physical system that is isolated from its environment is:

Physics

1 answer:

kompoz [17]3 years ago

8 0

Closed

Explanation:

A physical system that is isolated from its environment is said to be a closed system.

In a closed system, energy can be exchange but matter cannot be exchanged.

A closed system sightly permits the only certain types of exchange.
These systems are usually used to control and limit the impact of the environment on a system.
Experiments can be conducted on the premises of any the interactions.

Learn more:

Momentum of an isolated system brainly.com/question/7973509

#learnwithBrainly

You might be interested in

A car traveling west at 70 miles per hour for 3 hours covers a distance of

gtnhenbr [62]

70x3=210 mph... its that easy

5 0

3 years ago

A single-turn current loop carrying a 4.00 A current, is in the shape of a right-angle triangle with sides of 50.0 cm, 120 cm, a

pantera1 [17]

Given that,

Current = 4 A

Sides of triangle = 50.0 cm, 120 cm and 130 cm

Magnetic field = 75.0 mT

Distance = 130 cm

We need to calculate the angle α

Using cosine law

$120^2=130^2+50^2-2\times130\times50\cos\alpha$

$\cos\alpha=\dfrac{120^2-130^2-50^2}{2\times130\times50}$

$\alpha=\cos^{-1}(0.3846)$

$\alpha=67.38^{\circ}$

We need to calculate the angle β

Using cosine law

$50^2=130^2+120^2-2\times130\times120\cos\beta$

$\cos\beta=\dfrac{50^2-130^2-120^2}{2\times130\times120}$

$\beta=\cos^{-1}(0.923)$

$\beta=22.63^{\circ}$

We need to calculate the force on 130 cm side

Using formula of force

$F_{130}=ILB\sin\theta$

$F_{130}=4\times130\times10^{-2}\times75\times10^{-3}\sin0$

$F_{130}=0$

We need to calculate the force on 120 cm side

Using formula of force

$F_{120}=ILB\sin\beta$

$F_{120}=4\times120\times10^{-2}\times75\times10^{-3}\sin22.63$

$F_{120}=0.1385\ N$

The direction of force is out of page.

We need to calculate the force on 50 cm side

Using formula of force

$F_{50}=ILB\sin\alpha$

$F_{50}=4\times50\times10^{-2}\times75\times10^{-3}\sin67.38$

$F_{50}=0.1385\ N$

The direction of force is into page.

Hence, The magnitude of the magnetic force on each of the three sides of the loop are 0 N, 0.1385 N and 0.1385 N.

8 0

3 years ago

A car has an acceleration of 4m/s^2 to the east for 5 seconds. What is the change in velocity?

Natali5045456 [20]

Answer:

a= 4m/s^2

t = 5 secs

v = at

v = 4 × 5

v =20 m/s

3 0

2 years ago

A ball having a mass of 200 g is released from rest at a height of 400 mm above a very large fixed metal surface. If the ball re

AysviL [449]

Answer:

0.9

Explanation:

h = 400 mm, h' = 325 mm

Let the coefficient of restitution be e.

h' = e^2 x h

325 = e^2 x 400

e^2 = 0.8125

e = 0.9

5 0

3 years ago

What is numbers 2 and 4? Please help, and many thanks to those who do chose to help.

Elan Coil [88]

Answer:

2. 6 km/h

4. 150 miles/h

5 0

3 years ago