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3 years ago

Tori applies a force of 20 newtons to move a bookcase with a mass of 40 kg. What

Physics

1 answer:

son4ous [18]3 years ago

5 0

Answer:

Acceleration, a = 0.5m/s²

Explanation:

Given the following data;

Force, f = 20N

Mass = 40kg

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

$Acceleration (a) = \frac{F}{m}$

Substituting into the equation;

$Acceleration (a) = \frac{20}{40}$

Acceleration, a = 0.5m/s²

Therefore, the acceleration of the bookcase is 0.5m/s²

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At what point is the KINETIC ENERGY at its highest?

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Answer:

An object has the MOST kinetic energy when it's movement is the GREATEST.

Explanation:

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2 years ago

F F= {mango, apple, banana, orange)

Stels [109]

Answer:

Explanation:

Cardinality of a set is the number of elements in that set. Given the set.

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3 years ago

A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and

victus00 [196]

Answer:

a) $t=195.948N.m$

b) $\phi=13.6 \textdegree$

Explanation:

From the question we are told that:

Density $\rho=1.225kg/m^2$

Velocity of wind $v=14m/s$

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient $\mu=2.05$

Generally the equation for Force is mathematically given by

$F=\frac{1}{2}\muA\rhov^2$

$F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2$

$F=163.29$

Therefore Torque

$t=F*r*sin\theta$

$t=163.29*1.2*sin90$

$t=195.948N.m$

Generally the equation for torque due to weight is mathematically given by

$t=d*Mg*sin90$

Where

$d=sin \phi$

Therefore

$t=sin \phi*Mg*sin90$

$195.948=833sin \phi$

$\phi=sin^{-1}\frac{195.948}{833}$

$\phi=13.6 \textdegree$

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2 years ago

A man travels 15 km east before turning around and heading 5 km west. What is his displacement?

navik [9.2K]

Answer:

10 km East

Displacement is the shortest path between two points.

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3 years ago

Read 2 more answers

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

babymother [125]

Answer:

Explanation:

height of pole = 15 ft

height of man = 6 ft

Let the length of shadow is y .

According to the diagram

Let at any time the distance of man is x.

The two triangles are similar

$\frac{y-x}{y}=\frac{6}{15}$

15 y - 15 x = 6 y

9 y = 15 x

$y=\frac{5}{3}x$

Differentiate with respect to time.

$\frac{dy}{dt}=\frac{5}{3}\frac{dx}{dt}$

As given, dx/dt = 4 ft/s

$\frac{dy}{dt}=\frac{5}{3}\times 4$

$\frac{dy}{dt}=\frac{20}{3}$ ft/s

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3 years ago