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3 years ago

1. In what type of ecosystem can monkeys population be found?

1 answer:

3 0

I, thank you for posting your question here at Brainly.

Here are the answers to your questions:

1. Monkeys live in tropical rainforest ecosystems.
2. Animals should be left alone in nature to take part in the balance of the ecosystem, and not upset it. A sudden increase of monkey population, probably due to destruction of rainforests which lead to lesser area of living for them.
3. Monkeys take a huge part in seed dispersal among flesh fruit plants. Without them, it will greatly affect the conservation of the forests.

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Energy of motion is known as what energy

GaryK [48]

Kinetic Energy = Energy of Motion

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3 years ago

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Why do concave lenses always form virtual images?

MaRussiya [10]

A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). The image of an object is found to be upright and reduced in size.

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4 years ago

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Ear "popping" is an unpleasant phenomenon sometimes experienced when a change in pressure occurs, for example,in an airplane. If

marshall27 [118]

Answer:

H = 0.00058m = 0.58mm of Mercury

h = 160m for popping at 8000m

Explanation:

Air density decreases with altitude (increasing height).

At sea level air density = 1.22kg/m^3

while at 3000m above it is approximately 0.8 kg/m^3

ASSUMPTION:

we neglect the change in density across 100m vertically

density of mercury = 13600kg/m ^3

we equate the pressure for mercury and air

AIR(pgh) = Mercury(pgh)

0.8 * g * 100 = 13600 * g * H

H = 0.00058m = 0.58mm of Mercury

At even farther heights, the air density further drops

at 8000m above it is 0.52kg/ m^3 (source:https://www.engineeringtoolbox.com/standard-atmosphere-d_604.html)

***for the ear to pop again, it has to experience same change in pressure as of at 3000m

Change in P for AIR at 3000m = Change in P for AIR at 8000m

ASSUMPTION : gravitational acceleration does not change with altitude

pgh = pgh

0.8 * g * 100 = .5 * g *h

h = 160m

3 0

4 years ago

Two speakers C & D are driven in step at 600 Hz by the same audio oscillator. these speakers both start out at 5.0 m from th

Mice21 [21]

Answer:

option B

Explanation:

given,

frequency of the speaker = 600 Hz

speed of sound = 340 m/s

wavelength = ?

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{340}{600}$

$\lambda = 0.567 m$

for second destructive interference,

the path difference,

$d =(2k-1)\dfrac{\lambda}{2}$

k = 2

$d =(2\times 2-1)\dfrac{\lambda}{2}$

$d =\dfrac{3\lambda}{2}$

$d =\dfrac{3\times 0.567}{2}$

d = 0.86 m

the correct answer is option B

3 0

4 years ago

A motorist is traveling at 20 m/s. He is 60 m from a stoplight when he sees it turn yellow. Is reaction time, before stepping on

Gnesinka [82]

V₀ = V₁ + 2ax
V₀ = final velocity which is 0 m/s
V₁ = initial velocity which is 20 m/s
x = distance which is 60-(0.5 x 20) =50m
this is because his reaction time is 0.5 sec so he traveled 10m before stepping on the break paddle.

a= (V₀-V₁) / 2x
= (0-20) / 2*50
= -0.2m/s
the negative is because it is a deceleration speed hence it is 0.2m/s

5 0

4 years ago