Answer:
V = 12.93 L
Explanation:
Given data:
Number of moles = 0.785 mol
Pressure of balloon = 1.5 atm
Temperature = 301 K
Volume of balloon = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values.
V = nRT/P
V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm
V = 19.4 L /1.5
V = 12.93 L
1.) Onomatopoeia - <span>The use of words whose sounds suggest their meanings.
Meow purred the cat as I scratched behind it's ear.
2.) Personification - </span><span>A figure of speech in which human qualities are attributed to an object, animal or idea.
</span><span>
The cat rolled it's eyes at it's humans obnoxious behaviour.
3.) Alliteration - </span><span>The repetition of sounds/letters at the beginning of a word.
</span>The keeper c<span>ouldn’t </span>k<span>eep all the cats in their cages.
</span><span>
4.) Pun - A play on words.
You have cat to be kitten me right now!
5.) Hyperbole - An over-exaggeration.
The cat jumped so high I swore it was going to the moon!
6.) Idiom - </span><span>A figurative meaning of the connotation of the word. (Different from the literal meaning.)
</span><span>
Well, she sure is another breed of cat, I'll tell you that!
(omg it rhymes too how exciting !!)
7.) Simile - </span><span>A comparison using like or as.
</span><span>
The cat's fur was as dark as night.
8.) Metaphor - </span><span>A comparison not using like or as.
</span><span>
The cat's fur was a blanket of warmth!!
Hope these examples helped !! :-)
</span>
Answer:
HOAc is stronger acid than HClO
ClO⁻ is stronger conjugate base than OAc⁻
Kb(OAc⁻) = 5.5 x 10⁻¹⁰
Kb(ClO⁻) = 3.3 x 10⁻⁷
Explanation:
Assume 0.10M HOAc => H⁺ + OAc⁻ with Ka = 1.8 x 10⁻⁵
=> [H⁺] = √Ka·[Acid] =√(1.8 x 10⁻⁵)(0.10) M = 1.3 x 10⁻³M H⁺
Assume 0.10M HClO => H⁺ + ClO⁻ with Ka = 3 x 10⁻⁸
=> [H⁺] = √(3 x 10⁻⁸)(0.10)M = 5.47 x 10⁻⁵M H⁺
HOAc delivers more H⁺ than HClO and is more acidic.
Kb = Kw/Ka, Kw = 1 x 10⁻¹⁴
Kb(OAc⁻) = 5.5 x 10⁻¹⁰
Kb(ClO⁻) = 3.3 x 10⁻⁷
Answer:
5.702 mol K₂SO₄
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Compounds
- Moles
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 993.6 g K₂SO₄
[Solve] moles K₂SO₄
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of K: 39.10 g/mol
[PT] Molar Mass of S: 32.07 g/mol
[PT] Molar mass of O: 16.00 g/mol
Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 4 sig figs.</em>
5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄
<span>All bulbs/plants and creatures </span>want nitrogen<span> to produce amino hallucinogen, proteid and DNA, although this </span>nitrogen<span> in the air is not in a manner that everybody can use.
For more information, look at the appendage below!</span>
