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4 years ago

when a substance donates a proton during a chemical reaction, that substance can be classified as a(an) ___ ?

Chemistry

1 answer:

Anarel [89]4 years ago

4 0

Answer:

An acid

Explanation:

According to the Arrhenius theory of acids and bases "an Arrhenius acid is a compound that increases the concentration of H+ ions that are present when added to water"

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What are the intervals on the fahrenheit scale called

Darya [45]

Fahrenheit temperature scale fâr´ənhīt˝ [key], temperature scale in which the temperature difference between two reference temperatures, the melting and boiling points of water, is divided into 180 equal intervals called degrees.

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3 years ago

H3PO4 what’s the name?

jasenka [17]

Answer:

Phosphoric acid

Explanation:

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3 years ago

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Mama L [17]

The answer to me is d

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3 years ago

After creating a Beer's Law plot using standard solutions of Q, you determined the slope of Beer's Law to be 0.598 M-1. Your unk

Mashutka [201]

Answer:

$C=0.247~M$

Explanation:

We have to start this question with Beer's Law, $A=E*b*C*$ . On this equation we will have:

A=Absorbance

E=Molar absorption coefficient

b= Optical path

C=Concentration

So, the question is: what values of this equation we know?. If we check the question we have the absorbance value "0.148" additionally we have the slope of the plot, this slope is the molar absorption coefficient, therefore E=0.598 M-1, finally we have also the optical path. The optical path is 1 cm for all devices, so b=1 cm. With all these values we can calculate the concentration "C".

$C=\frac{A}{b*E}$

$C=\frac{0.148}{1*0.598}$

$C=0.247~M$

So, we will have a concentration of 0.247 M

I hope it helps!

4 0

3 years ago

A certain substance x decomposes. it is found that 50% of x remains after 100 minutes. how much x remains after 200 minutes if t

fiasKO [112]

The time needed for a substance becomes half of it mass is called half-time, after. In this case, the half time is 100 minutes. Then to know how much substance remain after 200 minutes the equation would be:

Substance remains= 1/2^(time/half-time) x substance initial mass
Substance remains = 1/2^(200 minutes/100minutes) x 1 times= 1/4 times

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4 years ago