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3 years ago

What is the maximum number of electrons that can be contained in a f subshell?

Chemistry

1 answer:

schepotkina [342]3 years ago

8 0

The answer is 14, 14 electrons can be contained in a f subshell.

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The mass of a hypothetical planet is 1 100 that of the earth and it’s radius is 1 4 that of earth. If a person weighs 500 n on e

avanturin [10]

Answer: Your answer is 24

Explanation:

6 0

2 years ago

Measurements show that the energy of a mixture of gaseous reactants increases by during a certain chemical reaction, which is ca

TEA [102]

<h2>Endothermic and Exothermic</h2>

Explanation:

An exothermic response discharges heat and endothermic absorbs to heat
The whole of the enthalpies of the reactants is more prominent than the product, the response will be exothermic
In the product that the items side has a bigger enthalpy, the reaction is endothermic
An exothermic method is one that emits heat. This heat is transferred to the environment
An endothermic reactions is one in which heat must be provided to the system from the environment

8 0

2 years ago

Why is the C-14/C-12 ratio used to date once-living organisms?

ki77a [65]

Because C-12 is fixed value of any organisms but the value of C-14 is constantly decreasing by time thats why every organism have their specific ratio of C14/C12

8 0

3 years ago

A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and

IrinaK [193]

Answer:

34.02 g.

Explanation:

Hello!

In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

$PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\$

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

$MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol$

So probably, the gas may be H₂S.

Best regards!

6 0

3 years ago

What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

Slav-nsk [51]

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

$Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\ ml\\\\V = 33.33 \ ml$

Therefore, volume required is 33.33 ml .

5 0

3 years ago