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tino4ka555 [31]
3 years ago
13

An expandable container of oxygen has a volume of 30.0mL at a pressure of 36.7psi. If the pressure of the oxygen is reduced to 2

5.0psi what would the new volume of the contain be
Chemistry
2 answers:
LuckyWell [14K]3 years ago
8 0

Answer:

44.04 mL

Explanation:

From Boyle's law,

PV = P'V' ................................ Equation 1

Where P = initial pressure, V = initial volume, P' = Final pressure, V' = final volume.

make V' the subject of the equation

V' = PV/P'............................. Equation 2

Given: P = 36.7 psi, V == 30 mL = (30/1000) L = 0.03 L, P' = 25 psi.

Substitute into equation 2

V' = 36.7(0.03)/25

V' = 1.101/25

V' = 0.04404 L

V' = 44.04 mL.

Hence the new volume = 44.04 mL

ELEN [110]3 years ago
6 0

Answer:44.04mL

Explanation:Parameters given

V1 = 30.0mL

P1 = 36.7psi

P2 = 25.0psi

V2 = ??

From Boyle's gas law, which states that "the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature"

This means that,

the pressure of a gas tends to increase as the volume of the container decreases, and also the pressure of a gas tends to decrease as the volume of the container increases.

Mathematically, Boyle's can be represented as shown below

P= k/V

Where P = Pressure, V = Volume and k is constant

Therefore,

PV = k

P1V1 = P2V2 =PnVn

Using the formula

P1V1 = P2V2

V2 = P1V1/P2

V2 = (36.7psi × 30.0mL) / 25.0psi

V2 = 1101.0/25.0

V2 = 44.04mL

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Delvig [45]

Answer:

32.4 mol

Explanation:

Given data:

Number of moles of C atom present = ?

Number of moles of glucose = 5.4 mol

Solution:

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There are 6 moles of C atoms are present in one mole of glucose.

In 5.4 moles of glucose:

5.4 mol × 6 = 32.4 mol

3 0
3 years ago
In the naturally occurring D series of ketoses, the carbonyl group is found on carbon number ___________, whereas in aldoses, th
Elena-2011 [213]

Answer:

second carbon atom from the  end

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Explanation:

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Carbohydrates can be classified based on structures,

Carbohydrates with the structure of alkanals (-CHO) are known as aldose while those of the structure of alkanones (C=O) are known as ketose.

In stereochemistry , D series is a kind of configurational arrangement where the hydroxyl group attaches itself to the right hand side.

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7 0
3 years ago
When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40
slava [35]
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

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7 0
3 years ago
What is the final volume?
zaharov [31]

Answer:

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Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 8 L

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 343 K

Final volume (V₂) =?

V₁ / T₁ = V₂ / T₂

8 / 293 = V₂ / 343

Cross multiply

293 × V₂ = 8 × 343

293 × V₂ = 2744

Divide both side by 293

V₂ = 2744 / 293

V₂ = 9.4 L

Therefore, the final volume of the gas is 9.4 L

6 0
3 years ago
In comparison to an atom of F-19 in the ground state, an atom of C-12 in the ground state has(1) three fewer neutrons
mel-nik [20]
(2) three fewer valence electrons is your answer.
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