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2 years ago

11

A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s ne

w volume?

1 answer:

maw [93]2 years ago

5 0

Answer:

8.68 L is the new volume

Explanation:

You use Boyle's law for this.

$P_{1}V_{1}=P_{2}V_{2}$

$P_{1}$ = first pressure

$P_{2}$ = second pressure

$V_{1}$ = first volume

$V_{2}$ = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)( $V_{2}$ )

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = $V_{2}$ = 8.68 L

Hope this helps :)

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Given that;

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$0.42 = \frac{[x][x]}{0.52-x}}$

$0.42 = \frac{[x]^2}{0.52-x}}$

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