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Viktor [21]
2 years ago
11

A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s ne

w volume?
Chemistry
1 answer:
maw [93]2 years ago
5 0

Answer:

8.68 L is the new volume

Explanation:

You use Boyle's law for this.

P_{1}V_{1}=P_{2}V_{2}

P_{1} = first pressure

P_{2} = second pressure

V_{1} = first volume

V_{2} = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)(V_{2})

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = V_{2} = 8.68 L

Hope this helps :)

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Answer:

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Net ionic equation:

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