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Viktor [21]
2 years ago
11

A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s ne

w volume?
Chemistry
1 answer:
maw [93]2 years ago
5 0

Answer:

8.68 L is the new volume

Explanation:

You use Boyle's law for this.

P_{1}V_{1}=P_{2}V_{2}

P_{1} = first pressure

P_{2} = second pressure

V_{1} = first volume

V_{2} = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)(V_{2})

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = V_{2} = 8.68 L

Hope this helps :)

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Answer:

The answer to your question is:

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b) 0.052 moles of Oxygen

Explanation:

Data

mass Iron = 3.86 g

moles = ?

Atomic weight Fe = 56 g

Process

a) Solve it using a rule of three

                                56 g of Fe ---------------- 1 mol

                               3.86 g ----------------------  x

                                x = (3.86 x 1) / 56

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b)

Balanced Equation

                              4Fe  +  3O₂  ⇒   2Fe₂O₃

Solve it using a rule of three

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