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atroni [7]
3 years ago
8

The isomerization of methylisonitrile to acetonitrile is first order in CH3NC. CH3NC(g) → CH3CN(g) The half life of the reaction

is 1.60 × 105 s at 444 K. What is the rate constant when the initial [CH3NC] is 0.030 M?
Chemistry
1 answer:
sasho [114]3 years ago
5 0

<u>Answer:</u> The rate constant for the given reaction is 4.33\times 10^{-6}s^{-1}

<u>Explanation:</u>

For the given chemical equation:

CH_3NC(g)\rightarrow CH_3CN(g)

We are given that the above equation is undergoing first order kinetics.

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

The rate constant is independent of  the initial concentration for first order kinetics.

We are given:

t_{1/2} = half life of the reaction = 1.60\times 10^5s

Putting values in above equation, we get:

k=\frac{0.693}{1.60\times 10^5s}=4.33\times 10^{-6}s^{-1}

Hence, the rate constant for the given reaction is 4.33\times 10^{-6}s^{-1}

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602,000,000,000,000,000,000,000 atoms

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2 years ago
Provide a balanced molecular equation, total ionic, and net ionic equation for sodium phosphate and zinc acetate.
vivado [14]

Answer: Balanced molecular equation :

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

Total ionic equation:

6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)  

The net ionic equation:

2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as  product.

The balanced molecular equation will be,

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

The total ionic equation in separated aqueous solution will be,

6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)

In this equation, and  are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

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2 years ago
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See below ~

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⇒ 6/1.2 = 5

⇒ 7.5/1.5 = 5

1. From this we understand that the calculated values of V/n remain constant, equal to <u>5</u> in this case.

2. The volume-mole graph will be a straight line passing through the origin. (Attached below)

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