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Evgen [1.6K]
3 years ago
13

Clearly, Atwood’s machine has a lot of systematic error that would not be present if we were to simplify the experiment. What is

one reason we might expect to get better results using Atwood’s machine rather than following Galileo’s example and just dropping objects off of tall buildings?
Physics
1 answer:
Sphinxa [80]3 years ago
4 0

Answer:

Better Equilibrium Maintenance for better accuracy...

Explanation:

In the Galileo's experiment, there is no utilization of two equal masses at a time. However, as we can see in a Atwood Machine, there are two equal masses involved that make the whole system to be in a state of equilibrium and ultimately the better measurements of acceleration due to gravity.

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Red Dwarf

Explanation:

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How much time would it take to go up to the moon and back
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3 years ago
Read 2 more answers
Explain what a coulomb is and be able to change from electron to coulomb and vice versa
torisob [31]

Answer:

Cuolomb is SI unit of charge

1 e=1.6022E-19 C

1 C = 6.2415E+18 e

Explanation:

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4 0
3 years ago
A remote ranch has a cylindrical water storage tank. It has a vertical central axis, a diameter of 24 ft, the sides are 5 ft hig
Effectus [21]

Answer:

Explanation:

From the given information:

The diameter of the pool = 24 ft

The radius will be = 24 ft/2 = 12 ft

The volume of water V = πr²(Δx)

V = π× 12²×(Δx)

V = 144π(Δx)

Le's assume water weighs 62.5 lb/ft³;

Then:

the Force (F) will be:

= 144π(Δx) * 62.5

= 9000πΔx  lb

Also, the side of cylindrical water = 5 ft while its depth = 4ft

As such, each slide of water d = 5 - x, and the region is between 0 and 4.

∴

The required work is:

W = \int^4_0 (5-x) 9000 \ \pi dx \\ \\ W = 9000 \int^4_0 (5-x) \ dx \\ \\ W = 9000 \pi \Big [5x - \dfrac{x^2}{2} \Big]^4_0 \\ \\  W = 9000 \pi \Big [5*4- \dfrac{4^2}{2} \Big]  \\ \\  W = 9000 \pi \Big [20-8 \Big]  \\ \\  W = 9000 \pi \Big [12 \Big]  \\ \\  W = 9000 \pi  (12) \\ \\ \mathbf{W = 108000 \pi \ ft.lb}

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3 years ago
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