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murzikaleks [220]
2 years ago
8

Can someone please help me!

Physics
1 answer:
Ratling [72]2 years ago
3 0

Answer: I've solved the above questions and attached pictures too which show the working for better understanding of the questions.

hope that helps...

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Help pls !!! Which statement is true for nuclear reactions but not for chemical reactions?
iris [78.8K]

Answer:

D

Explanation: this is why they have so much more energy released

7 0
3 years ago
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when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : dens
Mamont248 [21]

The density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

<h3>What is the relationship between acceleration and density?</h3>

For a solid falling through a viscous fluid, the acceleration of the object decreases until it attains terminal velocity.

The acceleration of the body increases with increase in density of the solid.

When density of solid = density of liquid, acceleration a = g

When density of solid = 2 × density of the liquid, acceleration a = g/2.

Therefore, the density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

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3 0
2 years ago
A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
kirill [66]

Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

Initial velocity ,u= 1.1 m/s

Final velocity ,v=3.7 m/s

d= 22.5 m

The force due to gravity along the incline plane = m g sinθ

The friction force = (m g)/5

Now from work power energy

We know that

work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2  g sinθ - ( 2 g)/5 ) d = v² -  u²

take g = 10 m/s²

(20 sinθ - ( 20)/5 ) 22.5 = 3.7² -  1.1²

20 sinθ - 4 =12.48/22.5

θ = 13.16 °

5 0
3 years ago
A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At
Pani-rosa [81]

The distance covered is 1000 m

Explanation:

The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

s=vt-\frac{1}{2}at^2

where

s is the distance covered

v is the final velocity

t is the time

a is the acceleration

For the rocket in this problem, we have:

v = 445 m/s is the final velocity

a=99.0 m/s^2 is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

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8 0
4 years ago
A _____ tide occurs when the ocean's surface reaches its maximum height in a particular place on any particular day.
Fed [463]

In one of the startling coincidences sprinkled throughout
every field of math and science, the moment of maximum
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4 0
3 years ago
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