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Kisachek [45]
3 years ago
5

Y- (-3y) combine the like terms to create an equivalent expression

Mathematics
2 answers:
erik [133]3 years ago
6 0

Hello there! :D

I love showing people how to use this concept, so lets get right to it! If you have trouble with negative (-) signs and how they interact with each other, I suggest you watch some Khan academy videos, it could realy help you in the future! :)

Alright, so here's the general rule: (multiplication and division)

-,-= +

-,+ = -

+,+=+

So, with this rule, I think we can solve!

Firstly, remember PEMDAS.

Let's look at the signs first. Two negatives equal a positive. Make the 3y in the parenthesis positive. Think of the negative sign as a -1 that is being multiplied by the (-3y) and the y.

That would look like this:

(y) (-1) (-3y)

Now we have:

y*(3y)

So when multiplying a variable by a variable, it becomes squared.

So, we would have 3y^2 or 3y^{2}

If you have any questions about this problem feel free to comment on this answer.

I hope this helped you and you have a wonderful day,

Kai xx

katen-ka-za [31]3 years ago
3 0

Answer:

4y

Step-by-step explanation:

y- (-3y)\\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\=y+3y\\\\=4y

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Find the area of the circle with a radius of 2 cm.
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a 12.56 cm2

Step-by-step explanation:

area = πr² or I'd

step 1: substitute (plug in) for r which in here is 2

π(2)²

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A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)²  +  (y/b)²   -  (z/c)²  =  1                         (1)

We have to find a , b, and c

We can express equation (1)

(x/a)²  +  (y/b)²    =  (z/c)² + 1                 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for  z = k       ( K = 1 , 2 , 3  and so on ) circles of different radius

(x/a)²  +  (y/b)²    =  (k/c)² + 1

at z = k = 0 at the base of the hyperboloid  d = 300   or r = 150 m

we have

(x/a)²  +  (y/b)²   = 1      

x²  +  y²   =   a²                a² = (150)²       a = b = 150

and    x²  +  y²  = (150)²

Now the other condition is at 200 m above the base d = 500 m   r = 250 m  minimum diameter then in equation (2)  we have:

(x/a)²  +  (y/b)²    =  (z/c)² + 1        

(1/a)² [ x² + y² ]  = (z/c)² + 1  

but   x²  +  y²  = r²    and in this case   r  =  250 m  then

(250)²/(150)²   =  (z/c)² + 1    ⇒ (62500/ 22500)  =  (200/c)² + 1

2,78  =  40000/c² + 1

2.78c²  =  40000  + c²

1.78c² = 40000

c²  =  40000/1.78

c²  = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)²   + y² /(150)² - z²/149,91  = 1

7 0
3 years ago
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