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valentinak56 [21]
3 years ago
5

I NEED HHELP ASAP STOP SENDING ME LINK

Mathematics
2 answers:
spayn [35]3 years ago
8 0
I’m pretty sure the answer is B
Ymorist [56]3 years ago
5 0

Answer:

The answer is B

Step-by-step explanation:

hope that helps

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Find the perimeter of the polygon
Zielflug [23.3K]

Answer:

100

Step-by-step explanation:

Okay so I'm not 100% sure but I think it's 100 because:

Angle B and D are the same, so the 12.5 areas will be the same (I honestly suck at explaining I'm really sorry.) But, if you add the sides from angle B and D it will be 50 because 12.5 + 12.5 + 12.5 + 12.5 (or 12.5 * 4). Meanwhile, For angle A and C, both outsides are the same as the other side.

I'm so sorry I can't explain the problem well but once you add them:

11.5 + 11.5 + 12.5 + 12.5 + 12.5 + 12.5 + 13.5 + 13.5 = 100

4 0
2 years ago
Simplify the expression - 3+(-2/5)
xxMikexx [17]

Answer:

The answer is -17/5

Step-by-step explanation:

hope that helps

6 0
3 years ago
Read 2 more answers
So can now the anser to math
Rama09 [41]

Answer:

Where is the picture?

Step-by-step explanation:

Have a great day

4 0
3 years ago
The administrator of a $200,000 trust fund must adhere to following guidelines.
skelet666 [1.2K]

Step-by-step explanation:

let us give all the quantities in the problem variable names.

x= amount in utility stock  

y = amount in electronics stock  

c = amount in bond

“The total amount of $200,000 need not be fully invested at any one time.”

becomes

x + y + c ≤ 200, 000,

Also

“The amount invested in the stocks cannot be more than half the total amount invested”

a + b ≤1/2 (total amount invested),

=1/2(x + y + c).

(x+y-c)/2≤0

“The amount invested in the utility stock cannot exceed $40,000”

a ≤ 40, 000

“The amount invested in the bond must be at least $70,000”

 c ≥ 70, 000

Putting this all together, our linear optimization problem is:

Maximize z = 1.09x + 1.04y + 1.05c

subject to

x+ y+ c ≤ 200, 000

x/2 +y/2 -c/2 ≤ 0

              ≤ 40, 000,

              c ≥ 70, 000

a ≥ 0, b ≥ 0, c ≥ 0.

3 0
2 years ago
A radio manufacturer believes that the length of life of WPPX model radio is normal with µ=12 years and σ=2.5 years. (a) What pe
kicyunya [14]

Answer:

(a) 5.48%

(b) 17.82 years

(c) 21.19%

(d) 15.21 years

Step-by-step explanation:

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

µ=12 years and σ=2.5 years.

(a) What percent of the radios will function for more than 16 years?

For x = 16

z = 16 - 12/2.5

z = 1.6

Probability value from Z-Table:

P(x<16) = 0.9452

P(x>16) = 1 - P(x<16)

1 - 0.9452

= 0.054799

Converting to percentage = 0.054799 × 100

= 5.4799%

Approximately = 5.48%

(b) Suppose the company decides to replace 1% of the radios. Find the length of the guarantee period. i.e. find X.

find the z score of the 99th percentile = 2.326

Hence:z = (x-μ)/σ

2.326 = x - 12/2.5

Cross Multiply

2.326 × 2.5 = x - 12

5.815 = x - 12

x = 12 + 5.815

x = 17.815

Approximately = 17.82 years

(c) What percent of the radios that will fail to satisfy the guarantee period of 10 years? , i.e. less than 10 years?

When x < 10

Hence,

z = 10 - 12/2.5

z = -0.8

Probability value from Z-Table:

P(x<10) = 0.21186

Converting to percentage

0.21186 × 100

= 21.186%

Approximately = 21.19%

(d) If 10% of the radios will function for more than X years, find X.

The z score would be : 100 - 10%

= 90th percentile z score

We find the z score of the 90th percentile = 1.282

Hence:z = (x-μ)/σ

1.282 = x - 12/2.5

Cross Multiply

1.282 × 2.5 = x - 12

3.205 = x - 12

x = 12 + 3.205

x = 15.205

Approximately = 15.21 years

4 0
2 years ago
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