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stiv31 [10]
3 years ago
15

an object of mass 4 kg is placed on an inclined plane at an angle of 60. if the object slides down the plane with an acceleratio

n of 3m/s, what is the coefficient of the kinetic friction
Physics
1 answer:
balandron [24]3 years ago
6 0

The forces on the  y axis are:

N-mgcos(60)=0   , wich becomes

N=mgcos(60)

Rember that the friction force is always contrary to the motion of an object and its formula is  f=μ * N

The forces in the x axis are:

-f + mgsin(60)= m * a

-μ*mgcos(60) + mgsin(60)=m*a  ,

μ = ( m*a - mgf=μ[sin(60) )/ ( mgcos(90) )


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A closed system consists of 0.5 kmol of ammonia occupying a volume of 6 m3. Determine (a) the weight of the system, in N, and (b
kiruha [24]

Explanation:

It is known that the molecular weight of ammonia (NH_{3}) is as follows.

   Molecular weight (NH_{3}) = 14 + 3 \times 1 = 17

(a)   Therefore, we will calculate the mass as follows.

     0.5 kmol \times (\frac{1000 mol}{1 kmol}) \times (\frac{17 g}{1 mol})

                       = 8500 g

Now, formula to calculate weight of the system in N is as follows.

            Weight = mass × g

             = 8500 g \times (\frac{1 kg}{1000 g}) \times (9.8 m/s^{2})

             = 83.3 N     (1 kg m/s^{2} = 1 N)

Hence, the weight of the system is 83.3 N.

(b)   Relation between specific volume and number of moles is as follows.

            v (m^{3}/kmol) = \frac{V}{n}

Therefore, calculate the specific volume as follows.

       V_m = \frac{6 m^{3}}{0.5 k mol}

                   = 12 m^{3}/k mol

Also,  

               v (m^{3}/kmol) = \frac{V}{m}  

            v = \frac{6 m^{3}}{8.5 kg}

               = 0.705882 m^{3}/kg

Therefore, we can conclude that the value of specific volume is 12 m^{3}/k mol  and 0.705882 m^{3}/kg.

6 0
3 years ago
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A research submarine has a 10-cm-diameter window that is 8.4 cm thick. The manufacturer says the window can withstand forces up
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Pnet = Po + dgh 

<span>Density of saltwater = 1030 kg/m^3. </span>

<span>Disregard the thickness. Assuming it's a circular window, then the area is pi(r^2). </span>

<span>d = 20 cm = 0.2 m </span>
<span>r = d/2 = 0.1 m </span>

<span>A = pi(r^2) </span>
<span>A = 3.14159265(.1^2) </span>
<span>A = 0.0314159265 m^2 </span>

<span>p = F/A </span>
<span>p = (1.1 x 10^6) / (0.0314159265) </span>
<span>p = 35,014,087.5 Pa </span>

<span>1 atm = 101,325 Pa </span>

<span>P = Po + dgh </span>
<span>h = (P - Po) / dg </span>
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3 years ago
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6. An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of t
zubka84 [21]

Answer:

The distance away the center of the earthquake is 1083.24 km.

Explanation:

Given that,

Speed of transverse wave = 9.1\ km/s

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Time = 71 sec

We need to calculate the distance of transverse wave

Using formula of distance

d=v\times t

d=9.1\times t....(I)

The distance of longitudinal wave

d=5.7\times (t+71)....(II)

From the first equation

t=\dfrac{d}{9.1}

Put the value of t in equation (II)

d =5.7\times(\dfrac{d}{9.1}+71)

\dfrac{9.1d-5.7d}{9.1}=71\times5.7

d0.3736=404.7

d =1083.24\ km

Hence, The distance away the center of the earthquake is 1083.24 km.

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Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
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MA_775_DIABLO [31]

Answer:

Halfway between B and A on the return leg.

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Your average SPEED for the entire trip will equal your constant speed as the time and distance increase at proportionate rates.

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When you turn around at B to return, your Displacement is now decreasing while your travel time continues to increase, so your average velocity decreases.

Lets say the distance from A to B is 90 km and your constant speed is 30 km/hr.

your average speed is 30 km/hr because you took 6 hrs to travel 180 km

We want to find your position when your average velocity is 30/3 = 10 km/hr

it took 3 hrs to go 90 km from A to B. Let t be the time lapsed since turn around

your displacement is given by d = 90 - 30(t)

and your total time of travel is t + 3 hrs

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10 = (90 - 30t) / (t + 3)

10(t + 3) = (90 - 30t)

10t + 30 = 90 - 30t

40t = 60

t = 1.5 hrs

This will occur when you are halfway between B and A

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