The text does not specify whether the resistance R of the wire must be kept the same or not: here I assume R must be kept the same.
The relationship between the resistance and the resistivity of a wire is

where

is the resistivity
A is the cross-sectional area
R is the resistance
L is the wire length
the cross-sectional area is given by

where r is the radius of the wire. Substituting in the previous equation ,we find

For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is

Therefore, the new resistivity must be 4 times the original one.
Answer:

Explanation:
Given data
time=0.530 h
Average velocity Vavg=19.0 km/s
To find
Displacement Δx
Solution
The Formula for average velocity is given as

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Explanation:
Answer:
Explanation:
Volume of lead object = volume of aluminium object = V
mass of lead object > mass of aluminium object
When both the objects immersed in water, the buoyant force acting on both the objects.
Buoyant force = Volume immersed x density of water x gravity
As the volume of both the objects is same, so the buoyant force acting on both the objects is same.
So, weight in air of lead object is more than the weight in air of aluminium object.