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Delicious77 [7]
3 years ago
6

What are test called in sciene

Chemistry
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

In the scientific method, an experiment is an empirical procedure that arbitrates competing models or hypotheses. Researchers also use experimentation to test existing theories or new hypotheses to support or disprove them

Explanation:

Brainliest?

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Please help!!<br><br>Show the electronic configuration of magnesium atom​.
Galina-37 [17]

Explanation:

Magnesium has atomic number 12. It will be distributed in K, L, M shell in the following way:

K shell can accommodate a maximum of 2 electrons.

L shell can accommodate a maximum of 8 electrons and

M shell will accommodate 2 electrons

So the configuration becomes 2, 8,3

3 0
3 years ago
Read 2 more answers
Calculate the moles of Cu in 7.4×1021 atoms of Cu.
IceJOKER [234]
1 moles -------- 6.02x10²³ atoms
 ?? moles ----- 7.4x10²¹ atoms

moles = 7.4x10²¹ / 6.02x10²³

 = 0.01229 moles

hope this helps!
5 0
4 years ago
How many moles of water will be produced from the combustion of 0.27 moles of CH3OH?
Valentin [98]

Answer:

0.54 mole of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3OH + 3O2 —> 2CO2 + 4H2O

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.

Thus, 0.54 mole of H2O is produced from the reaction.

5 0
3 years ago
The molar mass of argon is 40g / mol what is the molar mass of a gas if it effuses at 0.91 times the speed of argon gas
Effectus [21]
To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:

Let 1 = argon gas
      2 = unknown gas

r2 = 0.91r1
r1/r2 = 1/0.91

1/0.91 = √M2/M1 = √M2/40
M2 = 48.30 g/mol
8 0
4 years ago
What is the state of matter for H2O?
Vesnalui [34]
Solid, liquid, and gas⛽️
7 0
4 years ago
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