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anastassius [24]
3 years ago
5

The first eighteen chemical elements on the periodic table are described below in a series of statements. The first 1S letters o

f the alphabet (A-R) have been arbitrarily assigned to replace the standard chemical symbols for these elements.
From the information given below, determine the proper location of the "mystery" elements.

1) The following elements belong together in groups: BF, EQ, PR, DC, J0, NK, G& HIM
2) Element D has four valence electrons.
3) Element E has the greatest electronegativity in its period.
4) Element B has fairly low first and second ionization energies and a lower boiling point than the other member of its group.
5) Concerning chemical reactivity in one period, the following are in increasing order: MFL
6) Element A really doesn't have a family to call its own and is a diatomic gas at room
7) Element I will not combine with P or Q
8) Element G is larger than M
9) The compound that forms between R and K ions has the formula R2K3.
10) Element R is more metallic than its family partner
11) At room temperature, Element O is a diatomic gas, while J is a nonmetallic solid.
12) Element Qis heavier than M, but slightly larger than MM
13) When Element C loses its valence electrons, it has the same electron structure as neutral H
14) Element I has the highest nuclear charge of the elements listed.
15) N's first ionization energy is greater than K's
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer: The questions looks unclear

Explanation: Periodic table is a table that contains elements arranged according to their increasing atomic number.

1. D belongs to group 4

E. Belongs to group 7

B belongs to group 1

A belongs to group 8. A noble gas.

R belongs to group 3. K belongs to group 6 C belongs to group 1. H belongs to group 8

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Manganese forms several oxides when combined with oxygen. One of the oxides (Oxide 1) contains 63.2% of Mn and another oxide (Ox
Nina [5.8K]

Explanation:

Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.

A. One of the oxides (Oxide 1) contains 63.2% of Mn.

Mass of the oxide = 100g

Mass of Mn = 63.2 g

Mass of O = 100 - 63.2

= 36.8 g

Ratio of Mn to O = 63.2/36.8

= 1.72

Another oxide (Oxide 2) contains 77.5% Mn.

Mass of oxide = 100 g

Mass of Mn = 77.5 g

Mass of O = 100 - 77.5

= 22.5 g

Ratio of Mn to O = 77.5/22.5

= 3.44

Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.

B.

Oxide 1

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

Oxide 2

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

3 0
3 years ago
Plz answer quick
SCORPION-xisa [38]
It’s baron I got it right on edg
8 0
3 years ago
Read 2 more answers
a mixture of carbon and sulfur has a mass of 9.0 g. complete combustion with excess o2 gives 22.5 g of a mixture of co2 and so2.
photoshop1234 [79]
S + O2 → SO2 
<span>z / (32.0655 g S/mol) x (1 mol SO2 / 1 mol S) x (64.0638 g SO2/mol) = (1.9979 z) g SO2 </span>

<span>C + O2 → CO2 </span>
<span>(9.0-z) / (12.01078 g C/mol) x (1 mol CO2 / 1 mol C) x (44.00964 g CO2/mol) = (32.9776 - 3.66418 z) g CO2 </span>

<span>Add the two masses of SO2 and CO2 and set them equal to the amount given in the problem: </span>
<span>(1.9979 z) + (32.9776 - 3.66418 z) = 27.9 </span>
<span>Solve for z algebraically: </span>
<span>z = 3.0 g S</span>
7 0
3 years ago
How many molecules of carbon dioxide, CO2, are present in 388.1 grams?
swat32

Answer:

53.11× 10²³ molecules

Explanation:

Given data:

Number of molecules of CO₂ = ?

Mass of CO₂ = 388.1 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CO₂ = 12× 1 + 16×2

Molar mass of CO₂ = 44 g/mol

Now we will put the values in formula.

Number of moles = 388.1 g/ 44 g/mol

Number of moles = 8.82 moles

Now we will calculate the number of molecules by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

8.82 mol × 6.022 × 10²³ molecules / 1 mol

53.11× 10²³ molecules

6 0
3 years ago
The sum of the protons and neutrons in an atom is called the atomic number <br> True or False
olganol [36]
It is false, the atomic number is the number of protons and/or electrons in an atom on an element.
3 0
3 years ago
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