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anastassius [24]
3 years ago
5

The first eighteen chemical elements on the periodic table are described below in a series of statements. The first 1S letters o

f the alphabet (A-R) have been arbitrarily assigned to replace the standard chemical symbols for these elements.
From the information given below, determine the proper location of the "mystery" elements.

1) The following elements belong together in groups: BF, EQ, PR, DC, J0, NK, G& HIM
2) Element D has four valence electrons.
3) Element E has the greatest electronegativity in its period.
4) Element B has fairly low first and second ionization energies and a lower boiling point than the other member of its group.
5) Concerning chemical reactivity in one period, the following are in increasing order: MFL
6) Element A really doesn't have a family to call its own and is a diatomic gas at room
7) Element I will not combine with P or Q
8) Element G is larger than M
9) The compound that forms between R and K ions has the formula R2K3.
10) Element R is more metallic than its family partner
11) At room temperature, Element O is a diatomic gas, while J is a nonmetallic solid.
12) Element Qis heavier than M, but slightly larger than MM
13) When Element C loses its valence electrons, it has the same electron structure as neutral H
14) Element I has the highest nuclear charge of the elements listed.
15) N's first ionization energy is greater than K's
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer: The questions looks unclear

Explanation: Periodic table is a table that contains elements arranged according to their increasing atomic number.

1. D belongs to group 4

E. Belongs to group 7

B belongs to group 1

A belongs to group 8. A noble gas.

R belongs to group 3. K belongs to group 6 C belongs to group 1. H belongs to group 8

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Explanation:

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The antibiotic prontosil, developed by bayer pharmaceuticals in 1932, was used in saving the life of president roosevelt's son f
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Prontosil is a compound produced by the coupled reaction of an aryldiazonium ion and an aromatic compound.

<h3>What are diazonium compounds?</h3>

These are organic compounds in which there are ionic interactions between the azo group (-N₂⁺) and an anion X⁻.

The general structure is RN₂⁺X⁻.

  • R is the lateral chain that might be an aromatic ring, among other options.
  • N₂⁺ is the azo group
  • X⁻ is the anion

The azo group characterizes as being unstable and reactive. This property is because one of the N atoms has a positive charge.

-N⁺≡ N

<h3>What is the coupling reaction of aryldiazonium compounds?</h3>

Aryldiazonium salt reactions can occur in two ways,

  • Substitution reactions
  • Coupling reactions

Coupling reactions are the aromatic electrophilic substitution, where the aryldiazonium ion acts as an electrophile for an activated aromatic compound to attack it.

The coupling reaction occurs at the azo group level.

In the exposed example,

  • the benzene ring with sulfur bonded to oxygen atoms is the coupling component
  • the benzene ring with NH₂ and the azo group is the diazonium ion

In the attached files you will find the drawings.

You can learn more about diazonium compounds at

brainly.com/question/9061271

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using avogadro’s law
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explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

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