I believe that the answer is 11.5
Explanation:
so for this u have to use this equation where
Moles = number of particle/6.02×10^23
= 3.045 × 10^24/6.02×10^23
= 5.0581
write it to 3 S.F so 5.06 moles
Prontosil is a compound produced by the coupled reaction of an aryldiazonium ion and an aromatic compound.
<h3>
What are diazonium compounds?</h3>
These are organic compounds in which there are ionic interactions between the azo group (-N₂⁺) and an anion X⁻.
The general structure is RN₂⁺X⁻.
- R is the lateral chain that might be an aromatic ring, among other options.
The azo group characterizes as being unstable and reactive. This property is because one of the N atoms has a positive charge.
-N⁺≡ N
<h3>What is the coupling reaction of aryldiazonium compounds?</h3>
Aryldiazonium salt reactions can occur in two ways,
- Substitution reactions
- Coupling reactions
Coupling reactions are the aromatic electrophilic substitution, where the aryldiazonium ion acts as an electrophile for an activated aromatic compound to attack it.
The coupling reaction occurs at the azo group level.
In the exposed example,
- the benzene ring with sulfur bonded to oxygen atoms is the coupling component
- the benzene ring with NH₂ and the azo group is the diazonium ion
In the attached files you will find the drawings.
You can learn more about diazonium compounds at
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.5336
using avogadro’s law
The molar mass of the unknown gas is 184.96 g/mol
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>How to determine the molar mass of the unknown gas </h3>
The following data were obtained from the question:
- Rate of unknown gas (R₁) = R
- Rate of CH₄ (R₂) = 3.4R
- Molar mass of CH₄ (M₂) = 16 g/mol
- Molar mass of unknown gas (M₁) =?
The molar mass of the unknown gas can be obtained as follow:
R₁/R₂ = √(M₂/M₁)
R / 3.4R = √(16 / M₁)
1 / 3.4 = √(16 / M₁)
Square both side
(1 / 3.4)² = 16 / M₁
Cross multiply
(1 / 3.4)² × M₁ = 16
Divide both side by (1 / 3.4)²
M₁ = 16 / (1 / 3.4)²
M₁ = 184.96 g/mol
Learn more about Graham's law of diffusion:
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