Answer:
Explanation:
There are four quantum numbers:
Principal quantum number (n)
Azimuthal quantum number (l)
Magnetic quantum number (ml)
Spin quantum number (ms)
All these four quantum numbers gives complete information about an electron like its spin, shells, subshells and orbitals.
For example:
If l=3 than possible sets of quantum numbers are:
Azimuthal quantum number (l)
The azimuthal quantum number describe the shape of orbitals. Its value for s, p, d, f... are 0, 1, 2, 3. For l=3
(n-1)
4-1 = 3
it means principle quantum is 4 and electron is present in f subshell.
Magnetic quantum number (ml)
It describe the orientation of orbitals. Its values are -l to +l. For l=3 the ml will be -3 -2 -1 0 +1 +2 +3.
Spin quantum number (ms)
The spin quantum number tells the spin of electron either its clock wise (+1/2) or anti clock wise (-1/2).
If the electron is added in full empty orbital its spin will be +1/2 because it occupy full empty. If electron is already present and another electron is added then its spin will be -1/2.
The answer is B, sodium is an element.
Answer:
The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky
Explanation:
we have the following balanced reaction:
CaC2 + 2H2O = C2H2 + Ca(OH)2
the value of K for this reaction will be equal to:
K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)
if we multiply the reaction by the value of 6, we have:
6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2
Again, the value of K for this reaction will be equal to:
K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6
For the second reaction:
6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H
The value of K for this reaction:
K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)
we also have:
K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)
Thus:
K1 = K^6 * Ky
Answer:

Explanation:
From the question we are told that:
Pressure 
Temperature 
Volume 
Heat Produced 
Generally the equation for ideal gas is mathematically given by



Therefore


Since
Heat of combustion of Methane=889 kJ/mol
Heat of combustion of Propane=2220 kJ/mol
Therefore

Comparing Equation 1 and 2 and solving simultaneously




Therefore
Mole fraction 0f Methane is mathematically given as



B.) Because they both are Acids
Hope this helps!