Hello, we know that for a and b real numbers

So,

Thank you.
To solve this problem, we must imagine the triangles and
parallel lines which are formed. It is best to draw the triangle described in
the problem so that you can clearly understand what I will be talking about.
The first step we have to do is to make an equality equation
in triangle ABC.
In triangle ABC, we are given that lines XY and BC are two
parallel lines (XY || BC). Therefore
this means that:
AX / XB = AY / YC --->
1
The next step is to make an equality equation in triangle
AXC.
We are given that lines ZY and XC are two parallel lines (ZY
|| XC). Therefore this also means that:
AZ / ZX = AY / YC ---> 2
Combining 1 and 2 since they have both AY / YC in common:
AX / XB = AZ / ZX
we are given that:
AZ = 8, ZX = 4 therefore AX = AZ + ZX = 12, hence
12 / XB = 8 / 4
XB = 6
The answer has to be A.multiple by 3
I'm going to assume you've learn sin, cos, and tan. To find a you must do:

Once you find a, you can use the Pythagorean Theorem to find b:

Or you can do:

You can find these functions on a scientific calculator. Let me now if you need more help.
1) Linear model
R(t) = y = at + b
Where t is the year - 2000 (year since 2000)
For year 2006, t = 6; for year 2010, t = 10
Then:
1) 10.7 = a*6 + b
2) 34.2 = a*10 + b
Subtract (1) from (2)
34.2 - 10.7 = 10a -6a
23.5 = 4a
a = 23.5/4 = 5.875
Now from (1) 10.7 = 6a + b => b = 10.7 - 6a = 10.7 - 6*5.875 = - 24.55
Then the resulting model is R(t) = 5.875a - 24.55
2) Exponential model
R(t) = A[B]^t
(1) 10.7 = A[B]^6
(2) 34.2 = A[B]^10
Divide (2) by (1)
[34.2/10.7] = [B]^10 / [B]^6
3.1963 = [B]^4 => B = 1.3371
Now, from (1) 10.7 = A [1.3371]^6 => A = 10.7 / [1.337]^6 = 1.8725
Then, the model is R(t) = 1.8725{1.3371]^t