We have that
3sin x+cos²<span>x=2
</span>3sin x+(1-sin²x)<span>=2
</span>-sin²x +3sin x=1
sin²x -3 sin x+1=0---------> up to here the procedure is correct
let
A=sin x
then
A²-3A+1=0
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(A²-3A)=-1
Complete the square. Remember to balance the equation
by adding the same constants to each side.
(A²-3A+2.25)=-1+2.25
Rewrite as perfect squares
(A-1.5)²=1.25
(+/-)(A-1.5)=1.12
first solution
(A-1.5)=1.12--------> A=1.12+1.5-----> A=2.62-----> sin x=2.62
second solution
-(A-1.5)=1.12----> -A+1.5=1.12----> A=1.5-1.12----> A=0.38---> sin x=0.38
the answer is
the equation was factored incorrectly
Answer:
D
Step-by-step explanation:
Because 12 is greater than -5 and when you divide a postive and a negative you get a negative number. And negative numbers are less than 0 .
Answer:
H: Plots 1 & 2
Step-by-step explanation:
Step-by-step explanation:
The correct steps are:
2x²-2x-24=0
2(x²-x-12)=0
2(x-4)(x+3)=0
x=4 or x=-3
so what actually went wrong, is the final answer which is supposed to be <em>x=4,-3</em><em> </em>instead of x=-4,3
Answer:
I won't give you the answer straight away so you take the time to read my answer and understand
Step-by-step explanation:
We knoe that 2 to the third is 8. when you square to a negative power, you do squaring normally, and then take the reciprocal of that number. so 8 to the second power is 64, and we flip it over, sp the answer is 1/64
