Answer:
You can try afdah or 123 movies, maybe try Netflix if you have it
Explanation:
The sites do have ads but that's where I usually watch my movies
Answer:
Explanation:
The following code is written in Java and is a function/method that takes in an int array as a parameter. The type of array can be changed. The function then creates a counter and loops through each element in the array comparing each one, whenever one element is found to be a duplicate it increases the counter by 1 and moves on to the next element in the array. Finally, it prints out the number of duplicates.
public static int countDuplicate (int[] arr) {
int count = 0;
for(int i = 0; i < arr.length; i++) {
for(int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j])
count++;
}
}
return count;
}
Complete Question:
Assume that an array of Integers named a that contains exactly five elements has been declared and initialized. In addition, an int variable j has also been declared and initialized to a value somewhere between 0 and 3.
Write a single statement that assigns a new value to the element of the array indexed by j. This new value should be equal to twice the value stored in the next element of the array (i.e. the element after the element indexed by j ). Do not modify any other elements of the array!
Answer:
a[j] = 2 * a[j+1];
Explanation:
Since the array is named a and its indexes are referenced by the variable j
it means the elements of the array will be a[j] for (j=0; j=1;j=2).
The first element in the array (j=0) will be a[0], second element will be a[1] and so on.
The statement a[j] = 2 * a[j+1]; assigns a new value to the element of the array indexed by j, the value is equal to twice the value stored in the next element of the array (j+1).
