Answer:
12.44 g
Explanation:
2C4H10 + 13O2 = 8CO2 + 10H2O
n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).
n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).
Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.
mass of CO2 produced =
M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol
M = 0.5656/2 * 44
M = 0.2828 * 44
M = 12.44 of CO2
The boiling point of a liquid can be raised by adding pressure. Like wise, if you lower the pressure the boiling point goes down. This can be explained by the fact that boiling occurse when the vapor pressure equals the outside pressure so when the outside pressure rises the vapor pressure required for boiling also rises. Vapor pressure is proportional to temperature and therefore temperature needs to increase to make the vapor pressure increase.
I hope this helps. Let me know in the comments if anything is unclear or if you want me to explain anything further.
Answer:
0.16 J/g℃
Explanation:
We have the following data:
heat = 1,200 J
mass of metal = m = 150 g
change in temperature = ΔT = 50.0℃
The heat absorbed is calculated by using the following equation:
heat = m x Cp x ΔT
So, we introduce the data in the equation to calculate the specific heat of the metal (Cp), as follows:
Cp = heat/(m x ΔT) = (1,200 J)/(150 g x 50.0℃) = 0.16 J/g℃
The answer is <span>C.lithium (3), boron (5), and fluorine (9)</span>