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amm1812
3 years ago
11

Consider n2 (g) + 3h2 (g) →→ 2nh3 (g). what is the mass of nitrogen gas required to react with 0.129 g h2?

Chemistry
1 answer:
Flura [38]3 years ago
6 0
The given chemical reaction given above is already balanced such that the number of atoms in the left hand side of the equation is equal to that of the right hand side. Using the dimensional analysis, proper conversion factors and the molar masses,

                    mass of nitrogen = (0.129 g H₂)(1 mol H₂/2 g H₂)(1 mol N₂/3 mol H₂)(28 g N₂/1 mol N₂)
                     mass of nitrogen = 0.602 g N₂

Therefore, 0.602 g of nitrogen will be required for he reaction. 
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The correct answer is compound
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Identify the form of energy that is converted into ther- mal energy by your body
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What form of energy is converted into thermal energy by your body?<span>Identify the form of energy that is converted to into thermal energy in your body. Chemical, when you digest the food you eat</span>
7 0
4 years ago
Read 2 more answers
3. You measure a cube and determine that its sides are 0.65m. You place the cube on a mass scale and determine that this cube ha
amid [387]

The density of the cube in-

Kg/m³= 38.234 kg/m³

g/mL= 0.038234 g/mL

Explanation:

We know that volume of the cube equals m ³

Where “m” equals side of the cube

Given data-

Side of the cube=0.65m

mass of the cube= 10,500 gm

We know that 1000gm= 1 kg

Hence, 10,500 gm= 10.5 kg

Volume of the cube= (0.65)³

∴ Volume= 0.274625 m ³

We know that density = mass/volume

⇒Substituting the value of mass and volume, we get-

⇒Density= 10.5/0.274625= 38.234 kg/m³

We know that 1 kg/m³= 0.001 g/mL

Hence 38.234 kg/m³ would equal 0.038234 g/mL

Hence the density of the cube is 38.234 kg/m³ and 0.038234 g/mL

7 0
3 years ago
For the reaction o(g) + o2(g) → o3(g) δh o = −107.2 kj/mol given that the bond enthalpy in o2(g) is 498.7 kj/mol, calculate the
Aneli [31]
The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
∴ Averange bond enthalpy of O3(g) is 297.45kJ/mol.
8 0
4 years ago
you measure the depth to the bottom with a lead line and find out the bottom is 6000 meters deep. How many seconds would it take
son4ous [18]
<h3>Answer:</h3>

7.838 seconds

<h3>Explanation:</h3>
  • Assuming the sound of sound in seawater is 1531 m/s we can calculate the time taken by the signal to leave the ship and back.
  • The depth to the bottom is 6000 meters
  • The sound signal will cover the distance twice, to and fro the bottom to the ship.
  • Time is calculated by dividing the distance by the velocity or speed.

In this case;

Time = (2× distance) ÷ velocity

        = (2×6000) m ÷ 1531 m/s

        = 12000 m ÷ 1531 m/s

        = 7.838 s

Therefore, it will take 7.838 s for the sound signal to leave the ship and bounce back off and return to the ship.

7 0
4 years ago
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