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Maksim231197 [3]
3 years ago
15

Which of the following groups of atoms are most likely to have similar properties?

Chemistry
2 answers:
erik [133]3 years ago
7 0

Answer:

fluorine (9), iodine (53), and astatine (85)

Explanation:

Nezavi [6.7K]3 years ago
6 0
The answer is <span>C.lithium (3), boron (5), and fluorine (9)</span>
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C3H8+5O2a3CO2 +4H2O is an example of a __________ chemical reaction. A. synthesis. B. combustion. C. replacement. D. synthesis a
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B .combustion because HOH and CO2 are the products of complete combustion
7 0
3 years ago
What energy output objects work with the turbine?
MrMuchimi

The energy output object that works with the turbine is the alternator (generator)
8 0
3 years ago
The compound NaOH(s) dissolves in water to yield what ?
aalyn [17]
<span>NaOH + H2O = Na+ and OH- ions.</span>
3 0
4 years ago
The following reaction was performed in a sealed vessel at 791 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at
OlgaM077 [116]

Answer:

4.31 × 10²

Explanation:

Equation of the reaction;

H_{2(g)} + I_{2(g)}     ⇌     2HI_{(g)

The ICE Table is shown as follows:

                            H_{2(g)}         +         I_{2(g)}        ⇌     2HI_{(g)

Initial                    3.10                     2.50                  0      

Change                 - x                       -x                     + 2x      

Equilibrium        (3.10 - x)                0.0800              2x

From I_{2(g)}   ;

We can see that 2.50 - x = 0.0800

So; we can solve for x;

x = 2.50 - 0.0800

x = 2.42

H_{2(g)}  which = (3.10 -x) will be :

= 3.10 - 2.42

= 0.68

2HI_{(g) = 2x

= 2 (2.42)

= 4.84

K_c = \frac{[HI]^2}{[H_2][I_2]}

K_c = \frac{(4.84)^2}{(0.68)(0.0800)}

K_c =\frac{23.4256}{0.0544}

K_c = 430.62

K_c ≅ 431

K_c = 4.31 × 10²

6 0
3 years ago
The accepted value of ksp is 1.2×10^−12 for Ag2CrO4. Calculate the percentage error if your experimentally determined value for
sweet-ann [11.9K]
%error = |(original value - mistaken value)| / original value * 100%

Original value = 1.2 x 10^-12
Mistaken value = 1.7 x 10^-10

%error = | [(1.2 x 10^-12) - (1.7 x 10^-10)] | / 1.2 x 10^-12 x 100%

%error = (1.688 x 10^-10 / 1.2 x 10^-12) x 100%

%error = 1.172222222 x 10^17
8 0
2 years ago
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