Answer:
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g)
Explanation:
The equation Zn + 2 HCI -> H₂ +zncl2 on reduction and oxidation, it results as below;
- 2H+ + 2e- => H2 ; reduction
- Zn => Zn²+ + 2e- ; oxidation
The equations above are half cell.
On combination of the above half cell reaction equations gives;
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).
Therefore, the half reaction equation for Zn + 2 HCI -> H₂ +zncl2 is given by;
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).
glucose, ADP (adenosine diphosphate) and NAD.
Electrolytic cell negative
Explanation:
Sodium has atomic number of 11 and its electronic configuration is given by:
![[Na]=1s^22s^22p^63s^1](https://tex.z-dn.net/?f=%5BNa%5D%3D1s%5E22s%5E22p%5E63s%5E1)
The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.

![[Na^+]=1s^22s^22p^63s^0](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D1s%5E22s%5E22p%5E63s%5E0)
Sodium has single valency that is 1.
Let nbe the valency of the ion 'X'
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the formulas for all the possible compounds that sodium can form with the other ions will be:
