Answer : The correct option is, (b) +115 J/mol.K
Explanation :
Formula used :

where,
= change in entropy
= change in enthalpy of vaporization = 40.5 kJ/mol
= boiling point temperature = 352 K
Now put all the given values in the above formula, we get:



Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K
Ignore the point, the majority of the points are along the trend line.
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Hope this helps
Answer:
a) 6.5
b) pressure decreases
c)22 atm
Explanation:
Since the initial volume V1 is 5.40 L and the final volume V2 is 35.1 L, the ratio of V2:V1= 35.1/5.40= 6.5 hence the volume increases by a factor of 6.5.
When the volume increases, the pressure decreases accordingly in accordance with Boyle's law. Boyle's law states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.
c) From Boyle's law
Initial volume V1= 5.40 L
Final volume V2= 35.1 L
Initial pressure P1= 143 ATM
Final pressure P2 = the unknown
P1V1= P2V2
P2= P1V1/V2
P2 = 143 × 5.40/ 35.1
P2= 22 atm
Sorry my friend you don't have options so It can't be answered...