9514 1404 393
Answer:
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^0 = 1 . . . . for a ≠ 0
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And, it is convenient to know the cubes of small integers:
1³ = 1; 2³ = 8; 3³ = 27; 4³ = 64; 5³ = 125
6³ = 216; 7³ = 343; 8³ = 512; 9³ = 729; 10³ = 1000
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1) p^3 × p^5 = p^-12 × p^y
Equating exponents:
3 + 5 = -12 + y
20 = y . . . . . . . . . . . add 12
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2) 64 × 4^5 = 4^3 × 4^5 = 4^(3+5) = 4^8
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3) 10^x = 1 = 10^0
x = 0
Hello!
First, let's subtract.
20-1.08=18.92
Now let's add up each of our prices and see which one matches.
A) $19.92
B) $19.67
C) $18.92
D) $18.68
As you can see, our answer matches 
, so that is our answer.
I hope this helps!
We have 
.
The line passes through point (2, -1). Substitute the coordinates of the point to the equation of a line:
<h2>Answer: 3x - 4y = 10</h2>
Answer:
It's four.
Step-by-step explanation:
Doesn't require an explanation buuut.... Imagine you have two apples, and a friend gives you two more, you then have four apples.
The base will have the greatest area for a given perimeter if it is square. If the edge of the square base has length x (in feet), then the total material requirement in square feet is
.. m = x^2 +(4/x^2)*(4x)
.. m = x^2 +16/x
This will have a minimum where dm/dx = 0.
.. dm/dx = 2x -16/x^2 = 0
.. x^3 = 8 . . . . . . . . . . . . . . . multiply by x^2/2 and add 8
.. x = 2
The tank is 2 feet square and 1 ft high.
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You will note that it is half the height of a cube that has double the volume. This is the generic solution to all minimum cost open-top box problems. Actually, the costs of pairs of opposite sides are equal to each other and to the cost of the base. If material costs are not identical in all directions, that is the more generic solution.
