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Lena [83]
3 years ago
13

A teacher plans to buy air fresheners that cost $3.50 each. If the teacher can spend no more than $10 on the air fresheners and

has a $3 discount coupon, which inequality represents the number of air fresheners, x, the teacher can buy?
Mathematics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

Step-by-step explanation:

We need to create an equation to represent how many air fresheners the teacher can buy.

Teacher has $10 and a $3 discount coupon which would give her an extra $3 to spend. Each air freshener is $3.50.

x = number of air fresheners

($10 + $3) / $3.50 = x        can be written as $13/$3.50 = x

We add $10 and $3 because that gives us the total amount she has to spend.

We divide by $3.50 because that is the cost of each air freshener. The result is the number of air fresheners she can buy.

In this case.

$13/$3.50 = x

3.71 = x   BUT we can't buy part of an air freshener, so she can purchase 3 air fresheners.

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Which is the graph of g(x) = ⌈x + 3⌉?
77julia77 [94]
ANSWER

\boxed {D}


EXPLANATION


The given function is,

g(x) = ⌈x + 3⌉

The parent function of this ceiling function is

g(x) = ⌈x ⌉

When this function is shifted horizontally 3 units to the left, we obtain the transformed function,

g(x) = ⌈x + 3⌉


The correct answer is option D.

See attachment.

6 0
3 years ago
Monique bought 5 1/2pounds of chicken for $18.51. What was the cost per pound?
UkoKoshka [18]
About 3.40 rounded to the tenths place
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2 years ago
HELP ME PLSS BRAINIEST
zvonat [6]
(x-7)^2 = 12
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5 0
2 years ago
Read 2 more answers
Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap
bazaltina [42]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)

A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)

C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

AC=\sqrt{12^2+12^2}

AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

6 0
3 years ago
An arithmetic sequence has this recursive formula: (a^1 =8, a^n= a^n-1 -6
eduard

Answer:

a_n = 8 + (n - 1) (-6)

Step-by-step explanation:

Given

a_1 = 8

Recursive: a_{n} = a_{n-1} - 6

Required

Determine the formula

Substitute 2 for n to determine a_2

a_{2} = a_{2-1} - 6

a_{2} = a_{1} - 6

Substitute a_1 = 8

a_2 = 8 - 6

a_2 = 2

Next is to determine the common difference, d;

d = a_2 - a_1

d = 2 - 8

d = -6

The nth term of an arithmetic sequence is calculated as

a_n = a_1 + (n - 1)d

Substitute a_1 = 8 and d = -6

a_n = a_1 + (n - 1)d

a_n = 8 + (n - 1) (-6)

Hence, the nth term of the sequence can be calculated usinga_n = 8 + (n - 1) (-6)

3 0
3 years ago
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