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Pachacha [2.7K]
2 years ago
13

In what type of climate do trees produce narrower rings?

Chemistry
1 answer:
poizon [28]2 years ago
8 0

Answer:

cool and dry

                 

               

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If 2.0×10−4 moles of S2O2−8 in 170 mL of solution is consumed in 170 seconds , what is the rate of consumption of S2O2−8?
Ostrovityanka [42]

Answer : The rate of consumption of S_2O_2^{-8} is, 7.0\times 10^{-6}M/s

Explanation : Given,

Moles of S_2O_2^{-8} = 2.0\times 10^{-4}mol

Volume of solution = 170 mL = 0.170 L     (1 L = 1000 mL)

Time = 170 s

First we have to calculate the concentration.

\text{Concentration}=\frac{\text{Moles}}{\text{Volume of solution}}

\text{Concentration}=\frac{2.0\times 10^{-4}mol}{0.170L}

\text{Concentration}=1.2\times 10^{-3}M

Now we have to calculate the rate of consumption.

\text{Rate of consumption}=\frac{\text{Concentration}}{\text{Time}}

\text{Rate of consumption}=\frac{1.2\times 10^{-3}M}{170s}

\text{Rate of consumption}=7.0\times 10^{-6}M/s

Thus, the rate of consumption of S_2O_2^{-8} is, 7.0\times 10^{-6}M/s

8 0
3 years ago
When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from oC to 87°C
klio [65]
The answer:
<span>When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from  ?? oC to 87°C

application of charles law

charle's law tells that 

T1/ V1 = T2 / V2, T must be in kelvin

it is given that  V1 = 3.6 L, V2 = 15.5 L, 
T2= </span><span>87°C= 360.15 K
</span>
so to find T1,  T1 =(T2 / V2) x V1

T1= (360.15 / 15.5) * 3.6= 83.64° K = - 190.15° C


7 0
4 years ago
HELPPP MEEE ASAPP!!!
SVEN [57.7K]

Answer:

the answer is B 200%

Explanation:

cause its the second column

4 0
3 years ago
the combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110kg of carbon dioxide what is the limittin
mote1985 [20]

Answer:

Propane

Explanation:

From the question given, we were told that 0.1240 kg of propane reacted with excess oxygen to produce 0.3110kg of carbon dioxide.

Since the reaction took place in the presence of excess oxygen, therefore, propane is the limiting reactant as all of it is used up in the presence of excess oxygen.

4 0
3 years ago
Read 2 more answers
ANSWER: b <br> i hope i helped
Sergio [31]

Answer:

thanks

Explanation:

7 0
3 years ago
Read 2 more answers
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