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Pachacha [2.7K]
2 years ago
13

In what type of climate do trees produce narrower rings?

Chemistry
1 answer:
poizon [28]2 years ago
8 0

Answer:

cool and dry

                 

               

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What variable represents specific heat in the equation Q = mcAT?
Elan Coil [88]

Answer: A. The variable c

============================================

Explanation:

Q = heat transferred

m = mass

c = specific heat

\Delta T = delta T = change in temperature

4 0
3 years ago
A simplified version of the Periodic Table of the Elements is provided. What type of elements would you most likely find in the
vesna_86 [32]

Answer:

Transition elements are present in this region.

Explanation:

5 0
2 years ago
The instructions for the experiment direct you to prepare 30 mL of 1.5 M HCl solution. In the chemical closet, you locate an 18M
MAVERICK [17]

The volume of the 18M HCl needed to make the solution will be 2.5 mL.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must remain the same.

Since, mole = molarity x volume

Thus, molarity x volume before dilution = molarity x volume after dilution.

Mathematically, the equation is written as: m1v1 = m2v2

In this case, m1 = 18 M, m2 = 1.5 M, and v2 = 30 mL.

What we are looking for is v1, the amount of the stock HCl needed for dilution.

v1 = m2v2/m1 = 1.5 x 30/18 = 2.5 mL.

Thus, 2.5 mL of the stock HCl would be needed.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

6 0
2 years ago
Question 5<br> 5. CFC's break down<br> Ozone<br> carbon dioxide<br> Oxgygen<br> nitrogen
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Answer:

ozone. CFCs drift slowly upward to the stratosphere, where they are broken up by ultraviolet radiation, releasing chlorine atoms, which are able to destroy ozone molecules.

4 0
3 years ago
Read 2 more answers
If 10.5 g copper chloride react with 12.4 g aluminum what is the limiting reactant
Brut [27]
Molar mass of copper chloride is 134.45 g/mole, so the mole of 10.5 g copper chloride is 10.5/134.45 = 0.078 mole.  Molar mass of aluminum is 27 g/mole, so the mole of 12.4 g aluminium is 12.4/27 = 0.46 mole.  The formula of this reaction is as follows, 2Al + 3CuCl2 ⇒ 2AlCl3 + 3Cu. Thus the molar ratio of the reactants is Al:CuCl2 = 2:3. So to react with 0.078 mole of copper chloride, will need 0.078 x 2/3 = 0.052 moles of aluminum which is less than the given amount (0.46mole).  Therefore, copper chloride is the limiting reactant.
8 0
3 years ago
Read 2 more answers
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