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skelet666 [1.2K]
3 years ago
11

Which of the following elements is a metalloid

Chemistry
2 answers:
klemol [59]3 years ago
6 0
A metalloid can be:
 - Boron (B)
 - Silicon (Si)
 - Germanium ( Ge)
 - Arsenic (As) 
 - Antimony ( Sb)
 - Tellurium (Te)
 - Polonium (Po)

Hope this helps :)
irina1246 [14]3 years ago
6 0

Answer : Silicon is the element of Metalliod.

Explanation :

Metals : These are the elements that can easily loose electrons and forms cations.

For example : All the alkali or alkaline earth metals that is group 1 and 2 are the metals.

Non-metals : These are the elements that can easily gain electrons and form an anion.

For example : All the p-block elements that is group 13 to 18 are the non-metals.

Metalloids : These are the elements that shows both the property of metals and non-metals.

For example : Boron, silicon, germanium, arsenic, antimony, tellurium, polonium and astatine are the metalloids.

As per question, silicon is the elements of metalloids.

While, rubidium and vanadium are metals and radon is a noble gas.

Hence, the silicon is the element of Metalliod.

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Robert has 4 grams of a substance and Jill has 10 grams of the same substance. Which of the following statements is true?
ELEN [110]
If Robert has 4 grams of a substance and Jill has 10 grams of the same substance <span>Jill's sample will weigh more than Robert's sample.</span>
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How many moles of Boron are present in 20g of borax (sodium tetraborate)?​
stira [4]
20 grams of borax contains (20.0g) / (201 g mol -1) =0.10 mol of borax.

Therefore 0.40 mol of borax
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✞Why is propane stored in household tanks but natural gas is not?♡♡♡​
Klio2033 [76]

Answer:

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4 0
2 years ago
Does anyone know the answer to these?
Rashid [163]

Answer:

The answer to your question is below

Explanation:

Data

mass of CaCO₃ = 155 g

mass of HCl = 250 g

mass of CaCl₂ = 142 g

reactants = CaCO₃ + HCl

products = CaCl₂ + CO₂ + H₂O

1.- Balanced chemical reaction

             CaCO₃ + 2HCl   ⇒    CaCl₂ + CO₂ + H₂O

2.- Limiting reactant

molar mass of CaCO₃ = 40 + 12 + 48 = 100 g

molar mass of HCl = 2[1 + 35.5 ] = 73 g

theoretical proportion CaCO₃ /HCl = 100 / 73 = 1.37

experimental proportion CaCO₃ /HCl = 155 / 250 = 0.62

As the experimental proportion was lower than the theoretical proportion the limiting reactant is CaCO₃

3.-

Calculate the molar mass of CaCl₂

CaCl₂ = 40 + 71 = 111 g

          100 g of CaCO₃ ------------------ 111 g of CaCl₂

           155 g of CaCO₃ ----------------- x

               x = (155 x 111) / 100

               x = 17205 / 100

              x = 172.05 g of CaCl₂

4.- percent yield

Percent yield = 142 / 172.05 x 100 = 82.5 %

5.- Excess reactant

    100 g of CaCO₃  -------------------- 73 g of HCl

     155 g of caCO₃ ------------------- x

           x = (155 x 73)/100

           x = 133.15 g

Mass of HCl = 250 - 133.15

                    = 136.9 g

4 0
3 years ago
Mr. Avogadro has 20 grams of radioactive Pa-234. How many atoms of Pa-234 does Mr. Avogadro have? PLEASE HELP WILL MARK BRAINLIE
jolli1 [7]

Answer:

The number of atoms in 20 grams of Pa-234 is 5.14 ×10²² atoms

Explanation:

Given that the molar mass of Pa-234 (protactinium) is 234.04331, we have

The number of moles of protactinium in 20 grams of Pa-234, we have

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One mole of Pa-234 contains 6.02×10²³ atoms, therefore, we have;

0.0855 moles of Pa-234 contains 0.0855× 6.02×10²³  = 5.14 ×10²² atoms

Therefore, the number of atoms in 20 grams of Pa-234 = 5.14 ×10²² atoms.

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