Right answer is option d that o is oxidized.
Answer:
Option B. 4.25×10¯¹⁹ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 6.42×10¹⁴ Hz
Energy (E) =?
Energy and frequency are related by the following equation:
Energy (E) = Planck's constant (h) × frequency (f)
E = hf
With the above formula, we can obtain the energy of the photon as follow:
Frequency (f) = 6.42×10¹⁴ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 6.42×10¹⁴
E = 4.25×10¯¹⁹ J
Thus, the energy of the photon is 4.25×10¯¹⁹ J
Answer:
1)Filtration to remove sand
2)Evaporation to obtain sugar
Explanation:
Add water to the mixture and mix,sugar will dissolve.
Filter out the sand.
Evaporate the remaining solution to obtain the sugar.
Answer:
The energy of the photon is directly proportional to the frequency of the light emitting the photon.
Explanation:
Energy of the photon is given by expression:
E = Energy associated with the photon
= frequency of the light
h = Planck's constant =
c = speed of the light in vacuum = constant
=Wavelength of the photon
The energy of the photon is directly proportional to the frequency of the light emitting the photon.
