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riadik2000 [5.3K]

3 years ago

13

Find the center and radius of each circle x^2+y^2-6x+2y+9=0

1 answer:

harina [27]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

To obtain this form use the method of completing the square on both the x and y terms

x² - 6x + y² + 2y = - 9 ← rearranging

x² + 2(- 3)x + 9 + y² + 2(1)y + 1 = - 9 + 9 + 1

(x - 3)² + (y + 1)² = 1 ← in standard form

with centre (3, - 1) and radius 1

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Leroy uses 20 pounds of fertilizer to cover 4000 ft.² of his lawn and 50 pounds to cover 10,000 ft.². How much does he need to c

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3 years ago

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Pani-rosa [81]

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7 0

3 years ago

Read 2 more answers

1. Escribe como potencia los siguientes productos y luego resuelve como se indica en el ejemplo. a) 6.6.6 = 6 3 = 216 f) 11.11=

alexandr402 [8]

Answer:

(Véase la explicación para mayores detalles/See the explanation for further details)

Step-by-step explanation:

a) Tres al cubo (Three to cube):

$x = 3 \times 3 \times 3$

$x = 3^{3}$

$x = 27$

b) Seis al cubo (Six to cube):

$x = 6 \times 6 \times 6$

$x = 6^{3}$

$x = 216$

c) Cinco al cuadrado (Five squared):

$x = 5 \times 5$

$x = 5^{2}$

$x = 25$

d) Ocho al cuadrado (Eight squared):

$x = 8 \times 8$

$x = 8^{2}$

$x = 64$

e) Dos a la quinta (Two to five):

$x = 2 \times 2 \times 2 \times 2 \times 2$

$x = 2^{5}$

$x = 32$

f) Diez a la cuarta (Ten to four):

$x = 10\times 10 \times 10 \times 10$

$x = 10^{4}$

$x = 10000$

3 0

3 years ago

Rewrite the quadratic function in vertex form.<br> Y=3x^2-12x+4

chubhunter [2.5K]

Answer:

$\large\boxed{y=3(x-2)^2-8}$

Step-by-step explanation:

The vertex form of an equation of a parabola y = ax² + bx + c:

$f(x)=a(x-h)^2+k$

(h, k) - vertex

$h=\dfrac{-b}{2a},\ k=f(h)$

We have the equation:

$y=3x^2-12x+4\\\\a=3,\ b=-12,\ c=4$

Substitute:

$h=\dfrac{-(-12)}{2(3)}=\dfrac{12}{6}=2\\\\k=f(2)=3(2^2)-12(2)+4=3(4)-24+4=12-24+4=-8$

Finally:

$y=3(x-2)^2+(-8)=3(x-2)^2-8$

4 0

3 years ago