At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.
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What is Henry's Law ?</h3>
- According to Henry's law, the weight of a gas dissolved by a liquid is proportional to the pressure of the gas onto the liquid.
- With very few exceptions, a solute molecule in an extremely diluted solution will only have solvent molecules as its close neighbors. This means that the likelihood that a specific solute molecule will escape into the gas phase is predicted to be independent of the total concentration of solute molecules.
Solution:
The solubility of gas is directly proportional to partial pressure. It is expressed as:
S = 
where, S = Solubility of gas
= Henry's Law constant
= Partial pressure of gas
Now, put the values in above expression we get
0.060M =
× 0.9 atm
= = 0.066 M/atm
Now we have to find the partial pressure of He
0.150 M = 0.066 M/atm × 
= 2.27 atm
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Answer: experiments are use to test if an hypothesis is right or wrong
Explanation:
Let us assume that there is a 100g sample present. The respective mass of each element will then be:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Now, we divide each constituent's mass by its Mr to obtain the moles of each
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Dividing by the smallest number:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula is
C10H12NO
Answer: #2 : s, solid & #3 : PbBr2
Explanation: