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Viktor [21]
3 years ago
7

What power source uses the earths internal heat

Chemistry
1 answer:
nlexa [21]3 years ago
7 0

Answer:

Geothermal power comes from Earth's internal heat

Explanation:

The description applied to power sources tends to match the names applied to the source of energy. Sometimes Latin, or other word derivations are used.

For example, "hydro-" refers to water, so it is no surprise that hydroelectric power comes from the movement of water. Of course, "nuclear" refers to the nuclei of the atoms that are split to release energy in a nuclear power plant. Similarly, "geo-" refers to Earth, and "thermal" refers to heat, so "geothermal" energy is the name given to energy derived from Earth's heat.

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Gasses i’m pretty sure.
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3 years ago
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Consider the reaction below:
melisa1 [442]

Answer:

(A) first order reaction

Explanation:

A first order reaction is a type of reaction in which the rate of the reaction depends only on the concentration on one of the reactants. Since A is the only reactant we have, it is right to deduce that this reaction is a first order reaction.

Note: while the order of this reaction is 1, its molecularity is 2. The molecularity of a reaction is the number of moles of reactants that is actually reacting.

(B) is wrong

This is because a zero order reaction is one in which the rate of reaction is not influenced by the concentrations of the reactants and hence remains constant irrespective. Since we were not furnished with this idea in the question, it is only right that we reject this answer.

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4 years ago
B. If the sand you ran across has a specific-heat capacity of 835 J/(kgºc),
Murrr4er [49]

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Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m = mass of sand = 2 kg

c = heat capacity = 835J/kg^0C

Initial temperature  = T_i = 40^0C

Final temperature= T_f  = 50^0C

Change in temperature ,\Delta T=T_f-T_i=(50-40)^0C=10^0C

Putting in the values, we get:

Q=2kg\times 835J/kg^0C\times 10^0C

Q=16700J

16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C

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3 years ago
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Explanation:

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From the Sun.

Explanation:

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3 years ago
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