The balanced chemical reaction for the complete neutralization between HNO₃ and Ba(OH)₂ is given as,
2 HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ + 2 H₂O
Balanced equations
In order to balance the equation, the component atoms in the reactants and products must be the same in terms of number and mass.
Thus, in the above chemical equation, the number atoms of H, N, O, and Ba in the reactants and the products must be equal.
Therefore, the overall equation for the chemical reaction is,
2 HNO₃ (aq) + Ba(OH)₂ (aq) → Ba(NO₃)₂ + 2 H₂O
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cobalt has a larger atomic radius
2CuI (s) + I₂ (aq) → 2 Cu⁺² (aq) + 4 I⁻ (aq)
When writing an equilibrium expression, we use the following values:
A (aq) + 3B (aq) → 2C (aq) + 2D (aq)
The numbers were arbitrary molar equivalents and the uppercase letters are the molecules in the reaction. The species used in the equilibrium expression but all be in the same state, e.g., solid, liquid, aqeuous.
Kc = [C]²[D]² / [A][B]³
We write the formula by taking the concentration of the products, each to the power of their molar equivalent, and multiply them together. We then divide the products by the concentration of the reactants, also to the power of their molar equivalent.
Going back to the initial equation given, we can now write a Kc expression.
Kc = [Cu⁺²]²[I⁻]⁴ / [I₂]
It should be noted that the CuI (s) in the reaction was left out of the Kc expression. Pure solids and liquids are left out of the expression and only the aqueous species are included. The reason being that, in this case, solid CuI does not affect the amount of reactant at equilibrium. Therefore, we just leave the concentration for [CuI] = 1, and remove it from the expression.
Answer:
with 7 valence electrons.
Explanation:
Bromine has 7 unpaired (valence) electrons in its outer shell, and a total of 35 elecrons. Its <em>4s</em> orbital is completely filled with 2 electrons.
The closest answer from the options would be option D.
I hope this helps.
Answer:
Cl2, reacts with 55g of CS2. How much CC14 is produced? CS2 +3 Cl2 —-> CCl4 +S2C12
Explanation:
Cl2, reacts with 55g of CS2. How much CC14 is produced? CS2 +3 Cl2 —-> CCl4 +S2C12 sike firgue it out on your own