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3 years ago

Methods used by scientists

Chemistry

2 answers:

svet-max [94.6K]3 years ago

8 0

Answer:

scientific method

Explanation:

they use this alot

kaheart [24]3 years ago

8 0

Answer:

Make an observation.

Ask a question.

Form a hypothesis, or testable explanation.

Make a prediction based on the hypothesis.

Test the prediction.

Iterate: use the results to make new hypotheses or predictions.

Explanation:

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Who will win the super bowl? Kansas City Chiefs Or the Tampa Bay Buccaneers

Serga [27]

Answer: Kansas City Chiefs

Explanation: what ever you think.

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3 years ago

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What would be an evidence of release in energy?

shusha [124]

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3 years ago

Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is t

Rasek [7]

Answer:

$4.6*10^{-14}$ M

Explanation:

Concentration of $Cu^{2+} = [Cu(NO_3)_2]$ = 0.020 M

Constructing an ICE table;we have:

$Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}$

Initial (M) 0.020 0.40 0

Change (M) - x - 4 x x

Equilibrium (M) 0.020 -x 0.40 - 4 x x

Given that: $K_f =1.7*10^{13}$

$K_f } = \frac{[Cu(NH_3)_4]^{2+}}{[Cu^{2+}][NH_3]^4}$

$1.7*10^{13} = \frac{x}{(0.020-x)(0.40-4x)^4}$

Since x is so small; 0.40 -4x = 0.40

Then:

$1.7*10^{13} = \frac{x}{(0.020-x)(0.0256)}$

$1.7*10^{13} = \frac{x}{(5.12*10^{-4}-0.0256x)}$

$1.7*10^{13}(5.12*10^{-4} - 0.0256x) = x$

$8.704*10^9-4.352*10^{11}x =x$

$8.704*10^9 = 4.352*10^{11}x$

$x = \frac{8.704*10^9}{4.352*10^{11}}$

$x = 0.0199999999999540$

$Cu^{2+}= 0.020 - 0.019999999999954$

$Cu^{2+} = 4.6*10^{-14}$ M

8 0

3 years ago

A student needs to prepare 50.0 mL of a 1.20 M aqueous H2O2 solution. Calculate the volume of 4.9 M H2O2 stock solution that sho

Nonamiya [84]

Answer : The volume of 4.9 M $H_2O_2$ stock solution used to prepare the solution is, 12.24 ml

Solution : Given,

Molarity of aqueous $H_2O_2$ solution = 1.20 M = 1.20 mole/L

Volume of aqueous $H_2O_2$ solution = 50.0 ml = 0.05 L

(1 L = 1000 ml)

Molarity of $H_2O_2$ stock solution = 4.9 M = 4.9 mole/L

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1$ = Molarity of aqueous $H_2O_2$ solution

$M_2$ = Molarity of $H_2O_2$ stock solution

$V_1$ = Volume of aqueous $H_2O_2$ solution

$V_2$ = Volume of $H_2O_2$ stock solution

Now put all the given values in this formula, we get the volume of $H_2O_2$ stock solution.

$(1.20mole/L)\times (0.05L)=(4.9mole/L)\times V_2$

By rearranging the term, we get

$V_2=0.01224L=12.24ml$

Therefore, the volume of 4.9 M $H_2O_2$ stock solution used to prepare the solution is, 12.24 ml

3 0

3 years ago

You deposit $1000 into a savings plan at the end of each

Aloiza [94]

Answer:

FV = $3506.112

Interest = $506.112

Explanation:

We are given;

Annual deposit; A = $1000

Interest rate; i = 8% = 0.08

Number of years; n = 3

The value of the annuity after 3 years will be gotten from the formula;

FV = A[((1 + i)ⁿ - 1)/i](1 + i)

FV = 1000(((1 + 0.08)³ - 1)/0.08)(1 + 0.08)

FV = 1000(1.08⁴ - 1.08)/0.08

FV = $3506.112

Since you deposited $1000 each year, then after 3 years, total deposited = 3 × 1000 = $3000

Since FV = $3506.112, then interest = $3506.112 - $3000

Interest = $506.112

4 0

2 years ago