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EleoNora [17]
3 years ago
8

How many moles of Au2S3 is required to form 56 grams of H2S at STP?

Chemistry
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

0.55 mol Au₂S₃

Explanation:

Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.

1. Gather all the information in one place:

M_r:                          34.08

          Au₂S₃ + … ⟶ 3H₂S + …  

m/g:                             56  

2. Calculate the moles of H₂S

Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)

                      = 1.64 mol H₂S

3. Calculate the moles of Au₂S₃

The molar ratio is 1 mol Au₂S₃/3 mol H₂S.

Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)

                         = 0.55 mol Au₂S₃

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The balanced reaction is 3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s ).

<u>Explanation</u>:

A chemical equation is said to be balanced when the total number of atoms present on the reactants side is equal to the total number of atoms present on the product side.

The unbalanced chemical equation is as follows,

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To balance this equation, you need to look at how many atoms of each element are present on each side of the chemical equation.

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A number should be rounded up if
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Answer:

C.) The number after it is between 5 and 9

Explanation:

If the digit to the right is less than five, you must leave the digit you want to round to as it is.

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