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RoseWind [281]
3 years ago
9

If a mixture of gases contained 78% nitrogen at a pressure of 984 torr and 22% carbon dioxide at 345 torr, what is the total pre

ssure of the system?
Chemistry
1 answer:
AysviL [449]3 years ago
8 0

Answer:

P(total) = 1329 torr

Explanation:

Given data:

Pressure of nitrogen = 984 torr

Pressure of carbon dioxide = 345 torr

Total pressure of system = ?

Solution:

The given problem will be solve through the Dalton law of partial pressure of gases.

According to the this law,

The total pressure exerted by the mixture of gases is equal to the sum of partial pressure of individual gas.

Mathematical expression,

P(total) = P₁ + P₂ +.......+ Pₙ

Here we will put the values in formula,

P₁ = partial pressure of nitrogen

P₂ = partial pressure of carbon dioxide

P(total) = 984 torr + 345 torr

P(total) = 1329 torr

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Sergeeva-Olga [200]

Explanation:

Unsustainable way of managing resources means using resources in an unjustifiable manner, using without keeping in the needs for future generations. That is disobeying the principles of sustainability.

For examples release of toxic industrial wastes in rivers and thus, polluting it. Or, Deforestation of land for agricultural or industrial purposes. Thus, reducing the oxygen carrying capacity of Earth.

7 0
3 years ago
A 16 gram sample of O2(g) fills a container at STP.<br> What volume is the container?
sergij07 [2.7K]

Answer:

V = 11.2 L

Explanation:

Hello there!

In this case, according to the ideal gas equation:

PV=nRT

It is possible to compute the volume as shown below:

V=\frac{nRT}{P}

Whereas the moles are computed are computed given the mass and molar mass of oxygen:

n=16g*\frac{1mol}{32g} =0.5mol

Now, since the STP stands for a temperature of 273.15 K and a pressure of 1 atm, the resulting volume is:

V=\frac{0.5mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=11.2L

Best regards!

8 0
2 years ago
How are the elements within a row different?
NikAS [45]

Answer:

answer is b

Explanation:

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6 0
3 years ago
Read 2 more answers
Determine the pH of a 0.048 M hypochlorous acid (HClO) solution. Hypochlorous acid is a weak acid (Ka = 4.0 ✕ 10−8 M).
storchak [24]

pH of 0.048 M HClO is 4.35.

<u>Explanation:</u>

HClO is a weak acid and it is dissociated as,

HClO ⇄ H⁺ + ClO⁻

We can write the equilibrium expression as,

Ka = $\frac{[H^{+}] [ClO^{-}]  }{[HClO]}

Ka = 4.0 × 10⁻⁸ M

4.0 × 10⁻⁸ M = $\frac{x \times x }{0.048}

Now we can find x by rewriting the equation as,

x² =  4.0 × 10⁻⁸ × 0.048

   = 1.92 × 10⁻⁹

Taking sqrt on both sides, we will get,

x = [H⁺] = 4.38 × 10⁻⁵

pH = -log₁₀[H⁺]

     = - log₁₀[ 4.38 × 10⁻⁵]

   = 4.35

8 0
2 years ago
A student who is performing this experiment pours an 8.50 mL sample of the saturated borax solution into a 10 mL graduated cylin
belka [17]

Answer:

Ksp = 0.1762

Explanation:

Applying

a) moles of HCl added, n= CV=0.5×0.012 = 6×10-3mol

b) since 0.006mol is present in 0.012dm3 of HCl

It implies moles of borax

C) Concentration = 0.706M

Ksp = [0.5]^2[0.706]= 0.176

6 0
2 years ago
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