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kiruha [24]
3 years ago
13

What type of reaction is illustrated?

Chemistry
1 answer:
aev [14]3 years ago
8 0

Answer:

Double replacement is the answer

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Chlorofluorocarbons (CFCs) are no longer used as refrigerants because they destroy the ozone layer. Trichlorofluoromethane (CCl₃
Daniel [21]

Answer:

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

Explanation:

Entropy :It is defined as amount of energy which is unable to do work or the measurement of randomness or disorderedness in a system.

S=\frac{Q}{T(Kelvins)}

Molar heat of molar vaporization of Trichlorofluoromethane = 24.8 kJ/mol

Temperature at which Trichlorofluoromethan boils , T= 296.95 K

The molar entropy of the evaporation of Trichlorofluoromethan :

=\frac{24.8 kJ/mol}{296.95 K}=0.083516 kJ/mol K = 83.516 J/molK

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

8 0
3 years ago
The particle size of solute particles does not affects the rate. Question 14 options: True False
stepan [7]
The answer is false
8 0
3 years ago
Identify the compound in the following group that is most soluble in water. Match the words in the left column to the appropriat
gogolik [260]

Answer:

Following are the responses to the given points:

Explanation:

For question 1:

Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.

For question 2:

Butanoic acid is a rancid buffer.

Methanoic acid is responsible for the stinging red ants

For question 3:

Methyl butanoate's chemical structure.

8 0
3 years ago
One mole of a substance has the same number of particles as one mole of any other substance, regardless of what substances are b
katen-ka-za [31]
This is a true statement
3 0
3 years ago
Boron has two naturally-ocurring isotopes. Boron-10 has an abundance of 19.8% and actual mass of 10.013 amu, and boron-11 has an
aniked [119]

Answer:

Average atomic mass = 10.812 amu

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

<u>For first isotope, Boron-10: </u>

% = 19.8 %

Mass = 10.013 amu

<u>For second isotope, Boron-11: </u>

% = 80.2 %

Mass = 11.009 amu

Thus,  

Average\ atomic\ mass=\frac{19.8}{100}\times {10.013}+\frac{80.2}{100}\times {11.009}=1.982574+8.829218=10.811792

<u>Average atomic mass = 10.812 amu</u>

6 0
3 years ago
Read 2 more answers
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