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2 years ago

13

What type of reaction is illustrated?

1 answer:

aev [14]2 years ago

8 0

Answer:

Double replacement is the answer

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How is data not actually obtained from the experiment represented in a line graph? with a double line with only dots with a colo

Fittoniya [83]

The way how <span>data is not actually obtained from the experiment represented in a line graph is defnitely that </span><span>a colored line with a broken line. It is a well known fact that to obtain the actual data from the experiment you there should be plotted points on the line. Hope it will help you! Regards.</span>

7 0

2 years ago

Read 2 more answers

Quickly Please!!!!!!

FrozenT [24]

Answer:

$n=4.1mol$

Explanation:

Hello,

In this case, we can use the ideal gas equation:

$PV=nRT$

So we know the temperature, pressure and volume, therefore we can easily compute the required moles as shown below:

$n=\frac{PV}{RT}=\frac{2.0atm*101L}{0.082\frac{atm*L}{mol*K}*600K} \\\\n=4.1mol$

Best regards.

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2 years ago

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What is heat?<br> O Fire<br> O Hot<br> O Energy<br> O Potential

Law Incorporation [45]

Answer:

Energy

Explanation:

Heat is a form of energy.

5 0

3 years ago

No explanation needed, just a quick answer please!

tresset_1 [31]

all of the above is the answer :)

8 0

3 years ago

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

2 years ago