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Brrunno [24]
2 years ago
7

You are determining the density of an unknown solid. You figure out the volume by water displacement. Then you weigh the solid,

but forget to dry it off first. The calculated density will be larger, smaller, or the correct value? Why?
Chemistry
1 answer:
WINSTONCH [101]2 years ago
8 0

Answer:

The calculated density will be larger

Explanation:

The calculated density will be <u>larger</u>. Because, the volume is taken accurately, by the water displacement method. But, when we the took the mass, the water was present on the unknown solid. So, the mass of that water was added to the original mass of the solid. Hence, the mass measured was larger than the original mass. We, know from the formula of density that density is directly proportional to the mass of the object.

Density = Mass/Volume

Hence, the larger measured mass means the larger value of density.

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Mg + 2AgNO3 -&gt; 2Ag + Mg(NO3)2
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Answer:

Explanation:

We'll assume there is an excess of silver nitrate, so that all 12.0 moles of the magnesium (Mg) will react.

The balanced equation tells us we'll obtain 2 moles of Ag for every 1 mole of magnesium, for a molar ratio of 2/1.

Starting with 12.00 moles Mg, we would therefore hope to find twice that, or 24.00 moles of Ag.

To convert to grams, find the molar mass of Ag from the periodic table.

Ag has a molar mass of 107.9 (to 4 sig figs) grams/mole.

(24.00 moles)*(107.9 grams/mole) = 2590 grams (4 sig figs)

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