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xxMikexx [17]
3 years ago
6

B) 11' if I1 = 1,331. What’s the answer

Mathematics
1 answer:
sammy [17]3 years ago
6 0

Answer:

csc(x),x=<em><u>/</u></em><em><u>pi</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>i</u></em><em><u> </u></em><em><u>tink</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em>

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The scale on a map is 3 inches for every 6 1/4 miles. If the distance on the map is 5 1/2 inches, how far apart are the cities i
vovikov84 [41]
I think it is 34 3/8
4 0
3 years ago
A town has a population of 20000 and grows at 4% every year. What will be the population after 6 years, to the nearest whole num
zaharov [31]

Answer:

25306

Step-by-step explanation:

a=starting value = 20000

r=\text{rate = }4\% = 0.04

r=rate = 4%=0.04

\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.04=1.04

b=1+r=1+0.04=1.04

\text{Write Exponential Function:}

Write Exponential Function:

y=20000(1.04)^x

y=20000(1.04)  

x

 

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=20000(1.04)^{6}

y=20000(1.04)  

6

 

y= 25306.38037

y=25306.38037

7 0
2 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
A.<br> Create a model to show 2 x 5.
Rzqust [24]

Answer: You meant a picture?

Step-by-step explanation: The model is here:

6 0
2 years ago
Calculate the area of this triangle.<br> 13 cm<br> 5 cm<br> 12 cm-
inessss [21]

Answer:

78

Step-by-step explanation:

3 0
3 years ago
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