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3 years ago

I need help please!

Mathematics

1 answer:

Tanya [424]3 years ago

6 0

1234567 or reciprocal relations digital making

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Make X the subject of the formula will mark brainliest!!

irga5000 [103]

Answer:

$y = \frac{x + 2}{x - 4} \\ xy - 4y = x + 2 \\ xy - x = 4y + 2 \\ x(y - 1) = 4y + 2 \\ x = \frac{4y + 2}{y - 1} \\ \boxed{x = \frac{2(2y + 1)}{y - 1} }$

hope this helps.

3 0

2 years ago

My math final please help

spin [16.1K]

Answer:

m∠3 = 56

Step-by-step explanation:

Let's solve for x, first:

x + 9 = 3x - 85

9 = 2x - 85

94 = 2x

94/2 = x

47 = x

Now that we have x-value, we can substitute it in any one of the given equation to find angle 3 since, angle 1, 7 and 3 all are congruent:

=> m∠7 = x + 9

=> m∠7 = 47 + 9

=> m∠7 = 56

Since m∠7 ≅ m∠3

and m∠7 = 56, then

m∠3 = 56

Hope this helps!

6 0

3 years ago

Micayla wants the print shop to reduce the size of her painting but keep the ratio of length to width so that it will fit her fr

marissa [1.9K]

Answer:

The width of the frame must be 12 inches (15in by 12in)

Step-by-step explanation:

Given

See attachment for painting and frame

Required

Determine the dimension of the frame

To do this, we make use of the following scale ratio.

$Scale = Length : Width$

For the painting,

$Scale = 20: 16$

For the frame,

$Scale = 15: w$

Since she wants to maintain the same ratio; both scale must be the same.

i.e.

$15 : w = 20 : 16$

Express as fraction

$\frac{w}{15} = \frac{16}{20}$

$\frac{w}{15} = 0.8$

Make w the subject

$w = 15 * 0.8$

$w = 12$

The width of the frame must be 12 inches i.e. 15in by 12in frame

8 0

3 years ago

In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.

storchak [24]

The length of q, to the nearest 10th of a centimeter is 7.6 cm.

Given in question,

In ΔOPQ,

o = 9.2 cm

p = 2.4 cm

∠Q = 37°

Cosine formula ⇒ cos θ = $\frac{o^{2}+p^{2}-q^{2} }{2op}$

Putting the values in equation,

cos 37 = $\frac{(9.2)^{2}+(2.4)^{2}-q^{2} }{2*9.2*2.4}$

0.799 = $\frac{84.64 + 5.76-q^{2} }{44.16}$

0.799*44.16 = 90.4 - $q^{2}$

32.28 = 90.4 - $q^{2}$

$q^{2}$ = 90.4 - 32.28

$q^{2}$ = 58.12

$q = \sqrt{58.12}$

$q = 7.63$

q = 7.6 cm (to nearest 10th)

Hence, length of q is 7.6 cm.

Learn more about length on:

brainly.com/question/8552546

#SPJ1

3 0

1 year ago

2. Justin is 11.75 feet below sea level. He swims deeper into

Alenkasestr [34]

Answer:

he would be at 16.50ft. below sea level.

Step-by-step explanation:

If you are below sea level, the feet would be negative. -11.75 + -4.75 would be -16.50ft below sea level.

Let me know if this helps!!!!

5 0

3 years ago