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Mamont248 [21]
3 years ago
7

You roll a six sided number cube (die). What is the BEST answer for the probability that the number rolled is between 1 and 6? A

) certain B) unlikely C) impossible D) very likely
Mathematics
2 answers:
Ugo [173]3 years ago
5 0

Answer:

Very likely

Step-by-step explanation:

D, very likely a six sided die has numbers 1-6 so the chances of getting a 1-6 are 100%, and since very likely is the closest to all the time or 100% I'd say its the best answer.

NARA [144]3 years ago
4 0

Answer:

D) very likely

Step-by-step explanation:

The possible outcomes are 1,2,3,4,5,6

Between means 2,3,4,5

A) certain it is not certain because we could get 1 or 6

B) unlikely   we have a 4/6 change of getting our number rolled  so it is not unlikely

C) impossible we have a 4/6 change of getting our number rolled so it is not impossible

D) very likely   we have a 4/6 change of getting our number rolled  so it is better than 50 % we will have one of our numbers rolled

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A rectangular prism with a volume of 4 cubic units is filled with cubes with side lengths of 1/3 unit. How many 1/3 unit cubes d
Ghella [55]

Answer:

108 cubic units

Step-by-step explanation:

V  = 4 cubic units

v = (1/3)³ = 1/27 cubic units

V/v = 4/(1/27) = 4/1 x 27/1 = 108 cubic units

5 0
4 years ago
a local little League has a total of 60 players of whom 20%are left handed .how many left handed players are there?​
valentinak56 [21]

Answer:

Step-by-step explanation:

left handed players : 20% of 60

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0.20 * 60 = 12 are left handed

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
In a pair of similar polygons, corresponding angles are congruent.
Brilliant_brown [7]
This is true based on the theorem corresponding parts of congruent figures are congruent.
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3 years ago
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