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Readme [11.4K]
4 years ago
8

A 12-volume numbered set of books is placed randomly on a shelf. What is the probability that the books will be numbered in the

correct order from left to right?
Mathematics
1 answer:
spayn [35]4 years ago
5 0

Answer:

Step-by-step explanation:

There is a 1/12 probability that volume 1 will be correctly put in position 1.  

If we assume that volume 1 is right, then since there are then only 11 books left to choose from, there is then a 1/11 prob that volume 2 will be in position 2.  And so on. By the same reasoning there is 1/10 prob that volume 3 is then right, 1/9 prob for volume 4, 1/8 prob for volume 5, and 1/7 prob for volume 6,

and 1/6 prob for volume 7,and 1/5 prob for volume 8,and 1/4 prob for volume 9,and 1/3 prob for volume 10,and 1/2 prob for volume 11,and 1/1 prob for volume 12.  

So the probability is 1 /(12*11*10*9*8*7*6*5*4*3*2*1) = 1 / 479,001,600 ....

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Read 2 more answers
two consecutive odd number are such that three times the first is 5 more than twice the second. What are those two odd numbers?
Veseljchak [2.6K]
<h2>Answer:</h2>

The first consecutive odd number is: 9

and the second consecutive odd number is: 11

<h2>Step-by-step explanation:</h2>

Let the two consecutive odd numbers be: a and a+2

( Since, we know that the difference between two consecutive odd or two consecutive even numbers is always 2 )

Now, it is given that:

Three times the first is 5 more than twice the second.

i.e.

3a=5+2(a+2)\\\\i.e.\\\\3a=5+2a+4\\\\3a=5+4+2a\\\\3a=2a+9\\\\3a-2a=9\\\\a=9

Hence, we get:

The first consecutive odd number is: 9

and the  second consecutive odd number is: 9+2=11

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Answer:

96 pints

Step-by-step explanation:

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