Question

Two quadratic functions are shown.

Answer 1

Answer:

Function 1 has the least minimum value and its coordinates are (2, -7)

Step-by-step explanation: if you use an app or website called Desmos and type in the equations it will show you where they go on the graph and what the points are. Hope this helps!

Answer 2

Answer:

Function 1 has the least minimum value and its coordinates are (2, -7).

Step-by-step explanation:

Two quadratic functions are shown.

Function 1:

$f(x) = 2x^2 - 8x + 1$

Function 2:

x        g(x)

-2         2

-1         -3

0         2

1         17

LEts find the vertex to get the minimum value

to get the minimum value for function 1 we use formula $x=\frac{-b}{2a}$

$f(x) = 2x^2 - 8x + 1$, a=2, b=-8

$x=\frac{-b}{2a}=\frac{8}{2(2)}=2$

when x=2, the value of $f(2) = 2(2)^2 - 8(2) + 1=-7$

minimum point of function 1 is (2,-7)

For function 2, we find the minimum point using the table

minimum point of function 2 is (-1,-3)

Function 1 has the least minimum -7.

Function 1 has the least minimum value and its coordinates are (2, -7).