Answer:
sec(B)=b. ab/bc
sin(B)=c. ac/ab
csc(B)=f. ab/ac
cot(B)=a. bc/ac
tan(B)=e. ac/bc
cos(B)=d. bc/ab
Step-by-step explanation:
<u><em>SOHCAHTOA</em></u>
<u><em>Sine=Opposite/Hypotenuse</em></u>
<u><em>Cosine=Adjacent/Hypotenuse</em></u>
<u><em>Tangent=Opposite/Adjacent</em></u>
<u><em>SHACHOCotAO</em></u>
<u><em>Secant=Hypotenuse/Adjacent</em></u>
<u><em>Cosecant=Hypotenuse/Opposite</em></u>
<u><em>Cotangent=Adjacent/Opposite</em></u>
<u><em /></u>
Let the number be the variable x
4 times the number is 4x
the sum of 8 and 4 times a number is 28
4x+8=28
4x=28-8
4x=20
x=20/4
x=5
Answer:
6
Step-by-step explanation:
On the fourth day, there were b^3 beads and 216 beads on the belt, which means b^3 = 216. Taking the cube root of both sides, we have b = 6, which means there were 6 beads on the belt on the first day.
In order to find the value for 'w', you will need to cancel out -4w by adding 4w from the right side to the left side. You will have a equation of 4w=-28, but you will also need to have 'w' by itself so you will divide -28 to 4. Your final answer is -7.
