Answer with explanation:
Number of four digit numbers using four distinct digit
=Unit placed can be filled in four ways * Tens place can be filled in Three ways * Hundreds place can be filled in 2 ways * Thousand Place can be filled in a single way
=4*3*2*1
=24 distinct numbers
Sum of all four , four digits numbers using 1,2,3,4
= (If we keep 4 at unit place +Keeping 3 at unit place +Keeping 2 at unit place+Keeping 1 at unit place)×6+At tens place (2*2+3*2+1*2+4*2+2*2+1*2+1*2+3*2+4*2+2*2+3*2+4*2)+At hundred's place (2*2+3*2+1*2+4*2+2*2+1*2+1*2+3*2+4*2+2*2+3*2+4*2)+At thousand's Place(2*2+3*2+1*2+4*2+2*2+1*2+1*2+3*2+4*2+2*2+3*2+4*2)
=(24+18+12+6)Unit place+(60)Ten's place +(60)Hundred's place+(60)Thousand's Place
=66660
Answer:
did you try 12÷ by the decimal form of 3/4
14.69 in dollars and 6.2 percent
6y = - x + 8
y = - 1/6x + 4/3
y intercept = 4/3
Answer:
The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.
Step-by-step explanation:
Consider the provided information.
It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.
The probability of winning is 1/38. So, the probability of loss is 37/38.
Now, find the expected value of the game to the player as shown:
Hence, the expected value of the game to the player is -$0.2105.
Now find the expect to loss if played the game 1000 times.
1000×(-$0.2105)=-$210.5
Therefore, the expected loss if played the game 1000 times is -$210.5.
